In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of0.9 and a standard deviation of 2.39. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simplerandom sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.Question Help ▼What are the null and alternative hypotheses?O A. Ho H= 0 mg/dLO B. Ho: u>0 mg/dLH:µ< 0 mg/dLH: H#0 mg/dLO C. Ho H= 0 mg/dLO D. Ho: H=0 mg/dLH1:µ<0 mg/dLHy:H>0 mg/dLDetermine the test statistic.(Round to two decimal places as needed.)Determine the P-value.(Round to three decimal places as needed.)State the final conclusion that addresses the original claim.Ho- There isevidence to conclude that the mean of the population of changes0.Click to select your answer(s).5:16 PMlogitech99%P Type here to search4/8/2021DeleteDODF10F11F12InsertPrtScF7F8F9F6EscFnLockF3F4F5F1F2&BackspaceNumLock2381{T.YUPgUpRHomeQETabK LEnterFGH.JACapsLk12ShiftV BN MEndCPgUpEnd* 00小CO44

Name: In a test of the effectiveness of garlic for lowering cholesterol, 81
Uploaded: 2024-03-20T07:06:16.000Z
Channel: Bartleby
Description: In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/

From the provided information, Sample size (n) = 81 Sample mean (x̅) = 0.9 Sample standard deviation…

Math

Statistics

garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dl) have a mean o In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with 09 and a standard deviation of 2.39. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O B. H, >0 mg/dL O A. Ho =0 mg/dL H u#0 mg/dl. H, p<0 mg/dl O D. H =0 mg/dl. H us0 mg/dl OC. Ho =0 mg/dL H, u>0 mg/dL Determine the test statistic. L(Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim V Ho There is v evidence to conclude that the mean of the population of changes

garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dl) have a mean o In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with 09 and a standard deviation of 2.39. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O B. H, >0 mg/dL O A. Ho =0 mg/dL H u#0 mg/dl. H, p<0 mg/dl O D. H =0 mg/dl. H us0 mg/dl OC. Ho =0 mg/dL H, u>0 mg/dL Determine the test statistic. L(Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim V Ho There is v evidence to conclude that the mean of the population of changes

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Cholesterol levels in mmol/L on 10 patients were as follows: 1.50 1.95 1.84 2.20 1.68 2.41…

A: Cholesterol levels in mmol/L on 10 patients were as follows: X: 1.50 1.95 1.84 2.20 1.68…

Q: The scores of 40,000 county employees who took a recent civil service exam were normally distributed…

A: It is given that the scores follow normal distribution with mean 70 and standard deviation 10.…

Q: Low‑density lipoprotein, or LDL, is the main source of cholesterol buildup and blockage in the…

A: The 68-95-99.7% Rule:For a normal distribution, the empirical rule (68-95-99.7% Rule) state that…

Q: The data below are from an experiment comparing three different treatment conditions. What test…

A: Let μ1,μ2,μ3 denotes the means of the three different treatment conditions. Since the means of more…

Q: How is my work? Should anything be changed? A researcher wanted to examine the effect of a new…

A: As per our guidelines, we are allowed to answer first three sub-parts only. Thanks Instruction : How…

Q: The heights of women aged 20– 29 in the United States are approximately Normal with mean 64.2 inches…

A: The data for heights of both women and men are normally distributed. The mean is 64.2 inches and…

Q: The effect size is a measure of the magnitude of a treatment effect in standard deviation units.…

A: Given that, The effect size is a measure of the magnitude of a treatment effect in standard…

Q: Low‑density lipoprotein, or LDL, is the main source of cholesterol buildup and blockage in the…

A: 68-95-99.7% rule:In normal distribution, the empirical rule of 68-95-99.7% rule states that 68% of…

Q: Meteorologists in Texas want to increase the amount of rain delivered by thunderheads by seeding the…

A: Solution: n= 30 Sample size μ=300 Population mean

Q: a. Find the mean and standard deviation. b. What percentage of the data is within 1 standard…

A: Here , A medical laboratory tested 8 samples of human blood for acidity on the pH scale(xi)

Q: Almost all medical schools in the United States require students to take the Medical College…

A: (b) Obtain the standard deviation of the sampling distribution of their average score. The standard…

Q: a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds?…

A: Here Given Highest Speed measured=76.6 Mbps Sample Size=50 Sample mean=x¯=18.68 Sample sd= s= 37.17…

Q: If you choose one student at random, what is the probability that the student's score is between 505…

A: The scores follow a Normal distribution, and from published information, you know that the standard…

Q: Almost all medical schools in the United States require students to take the Medical College…

A: Introduction: Define X as the random variable of interest here, denoting the score of a randomly…

Q: The Addiction Severity Index (ASI) measures the impact of addiction on a person’s personal, family,…

A: Note: Hi there! Thank you for posting the question. As there are multiple sub parts, according to…

Q: The distribution of scores is approximately normal with a mean of 31 and a standard deviation of 5.…

Q: A researcher wants to evaluate the effectiveness of a patch he thinks will significantly decreases…

Q: For a sample of raw scores, you calculate a mean of 15.25 and a standard deviation of 3.19. What is…

A: Introduction:Suppose a random variable, X has sample mean, x̅ and sample standard deviation, s.For a…

Q: ly normal and has a standard deviation of 88% of students scored above a 800. What is the mean of

A: The mean of the binomial random variable obtained by the formula μ=np, where (n) is the number of…

Q: The scores on a psychology test were normally distributed with a mean of 65 and a standard deviation…

A: According to empirical rule 68%,95% and 99.7% data fall within one ,two and three standard…

Q: Glucose levels in patie tz free of diabetes are assumed to follow a normal distribution with a mean…

A: Here, mean is 120 and standard deviation is 16.

Q: The carapace length of an adult is normally distributed with a mean of 17.55 mm and a standard…

Q: A test has a mean score of 55 with a standard deviation of 12. Using the Empirical Rule determine…

Q: Almost all medical schools in the United States require students to take the Medical College…

Q: The width of an A4 piece of paper is normally distributed with a mean of 210 mm and a standard…

A: The width of an A4 piece of paper is normally distributed with a mean of 210 mm and a standard…

Q: If a regulation basketball is 12 PSI (pounds of force per square inch of area) with a standard…

A: Percentile : Percentile is the number such that certain percentage of data fall below that value.…

Q: A student is interested in knowing if there is a relationship between the age of a child and the…

A: Given: S.No x y 1 11 5 2 17 7 3 4 0 4 7 2 5 10 4 6 5 1 7 13 8 1.Null Hypothesis…

Q: If a z-score value of a data set is 1.35 what percentile does this correspond to?

Q: Is the height (in inches) of students in this class a quantitative or qualitative variable

A: Qualitative variable : It contains name or levels Example : eye colour, method of study...…

Q: A process is in statistical control with a mean of 79.5 mm and a standard deviation of 1.85. The…

A: The mean of the data is 79.5 mm. The standard deviation of the data is 1.85 mm. The upper…

Q: What is the test statistic for this procedure?

A: Assume that all conditions are met. The mean of the differences was 1.33 and the standard deviation…

Q: The Addiction Severity Index (ASI) measures the impact of addiction on a person’s personal, family,…

A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts. In case…

Q: You are provided with a mean of 28.18 with a standard deviation of 4.33. What percent of students…

Concept explainers

Inverse Normal Distribution

The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.

Mean, Median, Mode

It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.

Z-Scores

A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.

Topic Video

Question

In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of
0.9 and a standard deviation of 2.39. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple
random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Question Help ▼
What are the null and alternative hypotheses?
O A. Ho H= 0 mg/dL
O B. Ho: u>0 mg/dL
H:µ< 0 mg/dL
H: H#0 mg/dL
O C. Ho H= 0 mg/dL
O D. Ho: H=0 mg/dL
H1:µ<0 mg/dL
Hy:H>0 mg/dL
Determine the test statistic.
(Round to two decimal places as needed.)
Determine the P-value.
(Round to three decimal places as needed.)
State the final conclusion that addresses the original claim.
Ho- There is
evidence to conclude that the mean of the population of changes
0.
Click to select your answer(s).
5:16 PM
logitech
99%
P Type here to search
4/8/2021
Delete
DOD
F10
F11
F12
Insert
PrtSc
F7
F8
F9
F6
Esc
FnLock
F3
F4
F5
F1
F2
&
Backspace
Num
Lock
23
8
1
{
T.
Y
U
PgUp
R
Home
Q
E
Tab
K L
Enter
F
G
H.
J
A
CapsLk
1
2
Shift
V B
N M
End
C
PgUp
End
* 00
小
CO
44

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Centre, Spread, and Shape of a Distribution$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate the mean score ?μ of those who took the MCAT on your campus, you will obtain the scores of an SRS of students. The scores follow a Normal distribution, and from published information you know that the standard deviation is 10.810.8 . Suppose that, unknown to you, the mean score of those taking the MCAT on your campus is 495495 . In answering the questions, use ?z‑scores rounded to two decimal places. (a) If you choose one student at random, what is the probability that the student's score is between 490490 and 500500 ? (Enter your answer rounded to four decimal places.)
We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental US in Exercise 5.19. The mean and standard deviation of the reported differences are 1.1 degrees and 4.9 degrees respectively. see attachment
you Created a survey that meawere Depression In people. you want to test the Claim that the Mean. meusurements of Depression that peaple have is not egued to 6.5. A sample. of 145 Of you patients had a mean depression measurement of X=6.7 and a standard deviation of l,5.
Do wearable devices that monitor diet and physical activity help people lose weight? Researchers had 237 subjects who were already involved in a program of diet and exercise use wearable technology for 24 months. They measured their weight (in kilograms) before using the technology and 24 months after using the technology. The 237 differences in weight (weight after 24 months minus weight before using the wearable technology) had ?⎯⎯⎯=−3.5�¯and ?=7.8.. Let ?� be the mean weight difference. What is the test statistic? Give your answer to three decimal places. ?= Identify the correct interpretation of the results based on your analysis.Which is the correct answer ? There is very convincing evidence that there is a decrease in average weight after wearing the device. There is a small amount of evidence that there is a decrease in average weight after wearing the device. There is very convincing evidence that there is an increase in average weight…
Beth scored 88 on a nutrition test. The class mean was 81 and the standard deviation was 3.2. What is Beth's T-score? Group of answer choices 47.8 71.9 22.4 Beth's T-score cannot be calculated. Not enough information is provided.
An investigation of the relationship between traffic flow (measured in cars per day) and lead content (measured in micrograms per gram of dry weight) in the bark of trees near the highway yielded the following summary statistics: Sample Mean Sample Standard Deviation Lead Content (micrograms per gram dry weight) 680 240 Traffic Flow (cars / day) 1750 800 The correlation between lead content and traffic flow was found to be r = 0.6 and a scatterplot showed the form to be linear. Based on context, which is the X-variable and which is the Y-variable? Group of answer choices X-variable Y-variable
The empirical rule estabilishes the percentages that are 1,2, and 3 deviations from the mean True Flase
The overall average on a process you are attempting to monitor is 50.0 units. The process population standard deviation is 1.84. Sample size is given to be 16.
Consider a set of data in which the sample mean is 30.230.2 and the sample standard deviation is 7.87.8. Calculate the z-score given that x=31.4x=31.4. Round your answer to two decimal places.
The average home in the US is expected to cost $240,000. A random sample of 56 homes sold this month showed average price of $232,000. Assume you have access to this data. We are interested in determining cost if the cost of average home has decreased this month. If the test statistic is -1.66 what is the p-value?
3.34 Body Mass Index. Your body mass index (BMI) is your weight in kilograms divided by the square of your height in meters. Many online BMI calculators allow you to enter weight in pounds and height in inches. High BMI is a common but controversial indicator of overweight or obesity. A study by the National Center for Health Statistics found that the BMI of 2-year-old American male children is approximately Normally distributed, with mean 16.8 and standard deviation 1.9.2 a. What percentage of 2-year-old American male children have a BMI less than 15.0? b. What percentage of 2-year-old American male children have a BMI less than 18.5?
There is a new medication for diabetes, fifteen participants take the medication for fifteen days. The average blood glucose before taking the medication was 155 (population mean). The average blood glucose after taking the medication is 110. The standard deviation for the average glucose after taking the medication is 4.6. You want to evaluate if there is statistical evidence that there is a reduction in the mean glucose after taking the medication for 15 days. You must conduct a t-test. What is the t-statistic?