In a survey of 2009adults in a recent​ year, 704 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The​ 90% confidence interval for the population proportion p is ,. ​(Round to three decimal places as​ needed.) The​ 95% confidence interval for the population proportion p is ,. ​(Round to three decimal places as​ needed.) With the given​ confidence, it can be said that the ▼ population proportion sample proportion of adults who say they have made a New​ Year's resolution to eat healthier is ▼   greater than the lower endpoint less than the upper endpoint between the endpoints not between the endpoints of the given confidence interval. Compare the widths of the confidence intervals. Choose the correct answer below.     A. The​ 90% confidence interval is wider.   B. The​ 95% confidence interval is wider.   C. The confidence intervals are the same width.   D. The confidence intervals cannot be compared.

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: In a survey of 2494 adults in a recent​ year, 1446 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: A researcher found a 95% confidence interval for the proportion of college students who believe in…

A:

Q: In a survey of 2010 adults in a recent year, 713 made a New Year's resolution to eat healthier.…

A: Step 1:   Step 2: Step 3: Step 4:

Q: Suppose we wanted to estimate the average amount of sleep (in hours) a college student gets a night.…

A: Confidence interval : Confidence interval is a range of values it contains the true population…

Q: If n=28, (x-bar)=50, and s=10, construct a confidence interval at a 99% confidence level. Assume the…

A: Sample size n=28Sample mean=50Standard deviation =10

Q: In a survey of 2549 adults in a recent​ year, 1270 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2000 adults in a recent​ year, 708 made a New​ Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: In a survey of 2282​ adults, 749 say they believe in UFOs. Construct a 90% confidence interval for…

A:

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: In a survey of 2004 adults in a recent​ year, 717 made a New​ Year's resolution to eat healthier.…

A:

Q: If n-28, 2(x-bar)-38, and s-13, construct a confidence interval at a 98% confidence level. Assume…

A: Given : Sample Size, n = 28 Sample Mean, x̄ = 38 sample standard…

Q: na survey of 2587 adults in a recent year, 1365 say they have made a New Year's resolution.…

A: Given that  Sample size n =2587 Favorable cases x =1365 Sample proportion p^=x/n  =1365/2587 =0.5276

Q: If n=15, ¯xx¯=43, and s=11, construct a confidence interval at a 90% confidence level. Assume the…

A: Confidence interval is used to estimate the range of values within which the unknown parameters of…

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: The 90% confidence interval is from to. (Round to three decimal places as needed.)

A: A poll of 1030 adults in a country was conducted by telephone. Of those surveyed, 139 had…

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

A:

Q: Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying…

A: Solution: Given that, Estimate the proportion of students on her campus who eat cauliflower n=20 #…

Q: In a survey of 2325 adults, 711 say they believe in UFOs. Construct a 99% confidence interval for…

A: Suppose, p is the population proportion of all adults, who say that they believe in UFOs.

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: In a survey of 2071 adults in a recent year, 1300 say they have made a New Year's resolution.…

A:

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: In a survey of 2362 adults in a recent year, 1385 say they have made a New Year's resolution.…

A: Solution: Let X be the number of adults say they have made a New Year’s resolutions and n be the…

Q: If n=15, 7(x-bar)=50, and s-7, construct a confidence interval at a 80% confidence level. Assume the…

A: Sample mean =50Sample standard deviation = 7Sample size = 1580% confidence level

Q: In a survey of 2285 adults, 734 say they believe in UFOS. Construct a 95% confidence interval for…

A:

Q: In a survey of 2105 adults in a recent year, 737 made a New Year's resolution to eat healthier.…

A:

Q: In a survey of 2336 adults, 735 say they believe in UFOS. Construct a 90% confidence interval for…

A: Given that,In a survey of 2336 adults, 735 say they believe in UFOs.

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: In a survey of 2319 ​adults, 704 say they believe in UFOs.   Construct a 90% confidence interval for…

A:

Q: In a survey of 2308 adults, 724 say they believe in UFOS. Construct a 90% confidence interval for…

A: Solution: Let X be the number of adults who believe in UFOs and n be the sample number of adults.…

Q: 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare…

A: Answer Favorable cases [x] = 1230The sample size [n] = 2105

Q: of 100 people sampled, 50 had kids. The best point estimate for p is. The margin of error for a 90%…

A:

Q: Of the 1,000 people, 550 people used company s's smartphone and 460 people used company a's…

A: Given: n= 1000 ,x= 550.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence…

Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…

A:

Q: In a survey of 2071 adults in a recent year, 1281 say they have made a New Year's resolution.…

A: Given n=2071 x=1281

Q: In a survey of 2013 adults in a recent​ year, 731 made a New​ Year's resolution to eat healthier.…

A:

Q: In a survey of 2092 adults in a recent year, 748 made a New Year's resolution to eat healthier.…

A: Given data n=2092 x=748

Q: In a survey of 2055 adults in a recent​ year, 722 made a New​ Year's resolution to eat healthier.…

A: Givenx=722n=2055p^=xn=7222055=0.351

Q: In a survey of 2554 adults in a recent​ year, 1357 say they have made a New​ Year's resolution.…

A:

Q: If a 90%, a 95% and a 99% confidence interval are foung for a population mean, describe how the 3…

A: Population mean CI for known population standard deviation is, CI=x¯±Zσnwhere,σ=population standard…

Q: In a survey of 2445 adults in a recent​ year, 1491 say they have made a New​ Year's resolution.…

A: From the given information, let X be the number of adults have made a New Year’s resolution. X =…

Q: IF n=23, x-bar = 39, and s=3, find the margin of error at a 80% confidence level. Give answer to two…

A:

Q: What will be observed if calculated the three confidence intervals at 90%, 95%, and 99%? How would…

A: if three confidence intervals are calculated at 90% 95% 99%

Q: In a survey of 2409 adults in a recent year, 1235 say they have made a New Year's resolution.…

A: From the question, we know that:The sample size (n) is 2409The number of successes (x) is 1235