In a survey conducted by a reputable marketing agency, 231 of 1000 adults 19 years of age or older confessed to bringing and using their cell phone every trip to the bathroom (confessions included texting and answering phone calls). Construct a 95% confidence interval for the population proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom.

Q: Of 125 adults selected randomly from one town, 28 of them smoke. Construct a 99% confidence interval…

A: It is given that out of 125 adults in one town, 28 of them smoke. That is the value of n is 125 and…

Q: Suppose a consumer advocacy group wants to conduct a survey to find if the proportion of consumers…

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Q: As part of the Pew Internet and American Life Project,, researchers conducted two surveys in late…

A: Given: n1= 800 ,x1= 584 n2= 2253 ,x2= 1059 At 95.0 % confidence level , z score= 1.96 Need to find…

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: calculate the 95% confidence interval for the Presidential performance approval rating for a survey…

A: Solution: Let X be the number of people approved of the president’s performance and n be the number…

Q: ) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95%…

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Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: A bank randomly selected 200 checking-account customers and found that 110 of them also had savings…

A: Given that A bank randomly selected 200 checking-account customers and found that 110 of them also…

Q: confidence interval for the proportion of unemployed adults who have been unemployed for more than…

A: Here given  In a survey of 532 unemployed adults, 225 said that they had been unemployed for more…

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: The Centers for Disease Control and Prevention reported a survey of randomly selected Americans age…

A: Confidence interval for Proportions : The following is the formula for confidence interval of the…

Q: In a survey of 1005 adults 526 stated construct a 95% confidence interval

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Q: 2. In 2001, a Gallup poll surveyed 1016 households in the U.S about their pets. Of those surveyed,…

A: Given;n = 1016 x = 599p' = xn=5991016=0.58957

Q: The National Center for Health Statistics interviewed 5409 adult smokers in 2015, and 2636 of them…

A: Note:- As per our policy, we answer only 3 sub-parts at a time. Please make a new request for the…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: 2. n(1-P)= 3. N= If no N is given in the problem, use 1000000 N: Name the procedure The conditions…

A: Point and Interval estimate

Q: According the the U.S. Census bureau, the percentage of Santa Ana residents living in poverty is…

A: Given: p^1=0.177p^2=0.133n1=1200n2=1500

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

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Q: To assess the proportion of the readers of a magazine being professional, a random sample of 1000…

A: Given that the random sample of 1000 readers is selected and 660 are found to be professionals. That…

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: Out of 157 randomly selected adults in the United States who were surveyed, 77 exercise on a regular…

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Q: Suppose a marketing company computed a 96% confidence interval for the true proportion of customers…

A: The objective of the question is to understand the meaning of the given 96% confidence interval for…

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: Of 848 children surveyed, 144 plan to join a volunteer group in the future. Construct a 90%…

A: We have given that n=848, X=144, C.I=90%=0.90

Q: Out of a survey of 900 adults, 567 said that teenagers were more dangerous drivers than senior…

A: Givensample size(n)=900No.of adults said that teenagers were more dangerous divers(x)=567sample…

Q: In January 2010, a Gallup Poll asked a random sample of adults, “In general, are you satisfied or…

A: Given,n=1025x=256p^=xnp^=2561025=0.251-p^=1-0.25=0.75α=1-0.90=0.1α2=0.05z0.05=1.645

Q: Out of 42738 freshmen entering the State University system,  27298 of them need to take remedial…

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Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…