In a study to investigate whether women are really more talkative than men, the differencein the numbers of words spoken in a day by the male (male;) and female (female;) membersof 56 randomly selected couples (d; = male; — female;, i = 1, 2, ..., 56) was recorded andthe following summary statistics were produced:5656Σ di = -104,558, Σd = 4,605,935,512.i=1i=1(a) Calculate the sample mean and the sample variance for the differences.(b) State the null and alternative hypotheses for a paired t-test.=(c) Show that the test statistic is t -1.56 and hence determine whether the nullhypothesis can be rejected at the 5% significance level.

The question is based on paired t test Given : No. of randomly selected couples ( n ) = 56 ∑i=156 di…

Answered: In a study to investigate whether women…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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They sampled 361 people. People were allowed to self-identify as a heavy smoker or a non-smoker (mutually exclusive outcomes), and as diagnosed with lung cancer or not diagnosed with lung cancer (mutually exclusive outcomes). All surveyed people were under the age of 55, with similar age distributions in the smoking and not smoking categories. 343 people said that they did not smoke, and of those 343 people, 58 had been diagnosed with lung cancer. Only 18 people said that they were heavy smokers, and of those 18, 14 had been diagnosed with lung cancer. Please Calculate the expected count of people for each cell of the contingency table if the standard null hypo of the chi-square test of independent comes out to be true?
12. The rise of online streaming services such as Netflix and HBO Go has dramatically altered the media habits of Americans, especially young adults. A survey was conducted by interviewers at Princeton Data Sources. They selected a nationwide random sample of 384 adults and asked, "What is the primary way you watch television: cable, online streaming, or digital antenna?" The observed counts are given in the side-by-side frequency bar graphs below. Cable or satellite subscription Online streaming service Digital antenna 100 80 80- 60 40 Frequency 31 61 19 70 84 20- 15 10 0 18-29 30-49 50-64 65+ Ages (b) Which cell contributes the most to the chi-square statistic? Describe how the observed and expected counts differ for that category.
3. Of all the pupils in a particular school, 45 % go to school by bus. In a random sample of 30 pupils, calculate the mean and variance number of pupils that go to school by bus.
An article reported that in a particular year, there were 717 bicyclists killed on public roadways in a particular country, and that the average age of the cyclists killed was 43 years. These figures were based on an analysis of the records of all traffic-related deaths of bicyclists on public roadways of that country. (a) Does the group of 717 bicycle fatalities represent a census or a sample of the bicycle fatalities for that year? O a census O a sample (b) If the population of interest is bicycle traffic fatalities for this particular year, is the given average age of 43 years a number that describes a sample or a number that describes the population? O a number that describes a sample O a number that describes the population
64 owners and a similar age group of pet owners. The pet owners are matched one to one with the non-pet owners for income, number of close friendships, and 0. A researcher uses a matched-subjects design to in- than singles without pets. A mood inventory survey vestigate whether single people with pets are happier happier is given to a group of 20- to 29-year-old non-p general health. The data follow: Non-Pet Owner Pet Owner Matched Pair 12 14 8. 10 13 9. 9. D 13 E 10 12 F a. Is there a significant difference in the mood scores for non-pet owners versus pet owners? Test with a = .05 for two tails. b. Construct the 95% confidence interval to estimate the size of the mean difference in mood between the population of pet owners and the population of non-pet owners. (You should find that a mean difference of p, = 0 is an acceptable value, which is consistent with the conclusion from the hypoth- esis test.) %3D D. AB
Assume that 900 births are randomly selected and 443 of the births are girls. Use subjective judgment to describe the number of girls as significantly high, significantly low, or neither significantly low nor significantly high.
Medical researchers followed 6272 Swedish men for 30 years to see if there was any association between the amount of fish in their diet and prostate cancer. (“Fatty Fish Consumption and Risk of Prostate Cancer,” Lancet, June 2001). A summary of the data is given in the table below. Fish Consumption No Prostate Cancers Prostate Cancers Never/Seldom 110 14 Small part of diet 2420 201 Moderate part of diet 2769 209 Large part of diet 507 42 A) If a patient is randomly selected, what is the probability that he/she had prostate cancer given that fish was never or seldom a part of the diet? Round your answer to three decimal places and include the leading zero. B) If a patient is randomly selected, what is the probability that s/he ate fish as a large part of their diet given that they had prostate cancer. Round your answer to two decimal places and include the leading zero.
4. The numbers of incorrect answers on a true-false test for 15 students were recorded as follows: 2, 1, 3, 0, 1, 3, 6, 0, 3, 3, 5, 2, 1, 4, 2. Find the median and the mode.
About 4% of the population has a particular genetic mutation. 600 people are randomly selected. Find the mean for the number of people with the genetic mutation in such groups of 600. Submit Question acer

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