Homework Help is Here – Start Your Trial Now!
Science
Chemistry
In a study of the decomposition of nitrosyl bromide at 10 °C NOBrNO + ½ Br2 the following data were obtained: [NOBr], M 0.249 0.125 6.25×10-2 3.13×10-2 seconds 0 6.16 18.5 43.2 Hint: It is not necessary to graph these data. (1) The observed half life for this reaction when the starting concentration is 0.249 M is s and when the starting concentration is 0.125 M is s. (2) The average (1/[NOBr]) / t from t = 0 s to t = 6.16 s is M-1 s-1. The average (1/[NOBr]) / t from t = 6.16 s to t = 18.5 s is M-1 s-1. (3) Based on these data, the rate constant for this     order reaction is M-1 s-1.

In a study of the decomposition of nitrosyl bromide at 10 °C NOBrNO + ½ Br2 the following data were obtained: [NOBr], M 0.249 0.125 6.25×10-2 3.13×10-2 seconds 0 6.16 18.5 43.2 Hint: It is not necessary to graph these data. (1) The observed half life for this reaction when the starting concentration is 0.249 M is s and when the starting concentration is 0.125 M is s. (2) The average (1/[NOBr]) / t from t = 0 s to t = 6.16 s is M-1 s-1. The average (1/[NOBr]) / t from t = 6.16 s to t = 18.5 s is M-1 s-1. (3) Based on these data, the rate constant for this     order reaction is M-1 s-1.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question


In a study of the decomposition of nitrosyl bromide at 10 °C

NOBrNO + ½ Br2

the following data were obtained:

[NOBr], M 0.249 0.125 6.25×10-2 3.13×10-2
seconds 0 6.16 18.5 43.2



Hint: It is not necessary to graph these data.

(1)
The observed half life for this reaction when the starting concentration is 0.249 M is s and when the starting concentration is 0.125 M is s.

(2)
The average (1/[NOBr]) / t from t = 0 s to t = 6.16 s is M-1 s-1.
The average (1/[NOBr]) / t from t = 6.16 s to t = 18.5 s is M-1 s-1.

(3)
Based on these data, the rate constant for this 

 

 order reaction is M-1 s-1.

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Theories of Reaction Rates
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS