ndom sample of five drivers were asked to parallel park two cars having very different wheel bases and turning radi. The timerecorded and analyzed in Minitab. The output is given below.nce (Car_2 - Car_1)StDevSE Mean1.6730.748rean difference of parkig time (Car_2 - Car_1). At 5% significance level do the data provide sufficient evidence to conclude- 2 is significantly higher than that of car 1? Assume that the population of the differences is normally distributed.null and the alternative hypotheses of the test for this problem? (use only the signs: <, >,5, not equal, >=, ca)H1:tic =(Round to 2 decimal places)st =the test statistic =than the critical value, we (havel do not have)E statistic is (less / more)enough evidence to conclude that the parkimg time for car 2 is significantly higher than that of car 1. In a study of parking time, a random sample of five drivers were asked to parallel park two cars having very different whin seconds for each driver was recorded and analyzed in Minitab. The output is given below.Estimation fór Paired Difference (Car 2 - Car 1)MeanStDevSE Mean0.6001.6730.748Let p_d be the population mean difference of parkig time (Car 2 - Car_1). At 5% significance level do the data prouthat the parkimg time for car 2 is significantly higher than that of car 1? Assume that the population of the differencea. What are the signs of the null and the alternative hypotheses of the test for this problem? (use only the signs: <,>, ,rНоb. The value of the test statistic =(Round to 2 decimal places)ritical value of this test =d. The degrees of freedom of the test statistic =than the critical value, we (have. Conclusion: Since the test statistic is (less / more)enough evidence to conclude that the parkimg time for car 2 is significantly higher t

The sample size is 5, mean is 0.600, and standard error is 0.748.

Answered: In a study of parking time, a random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In order to evaluate a spectrophotometric method for the determination of titanium concentration, the method was uased on 64 alloy samples containing different certified amounts of titanium. For each alloy, eight different concentrations of titanium were made. Additionally, two spectrophotometer machines were used in the lab to control for possible variation between machines. Each machine received a random allocation of each concentration of alloy. Below you will find an ANOVA analysis for difference in certified mean concentrations detected using machines as a blocking fator. (You will have to calculate some of the values in the tables marked with ). Concentration 1.93 Machine 0.16 Residuals 14.27 Which one of the following is correct given the ANOVA table (using a 5% level of significance)? A. The method was able to detect the difference in the concentrations of titanium alloys; additionally, there was a detectable difference in the mean concentration between machines.…
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