Write the null and alternative hypotheses for carrying out an analysis of variance (ANOVA) on these data Total number of observations: 47======:Inference of Performance Score by Smoker status:Group Means with 95 Confidence IntervalsLowerMeanUpperactive20.7328.8737.00non smoker40.9848.6556.31passive28.7839.9351.08One-way Analysis of Variance (ANOVA F-test)F = 5.6049,p-value = 0.0067857### Difference in mean Performance_Score between Smoker_status groups(col group -row group)Estimatesactivenon smokernon smoker-19.78passive-11.078.71495% Confidence Intervals (adjusted for multiple comparisons)activenon smokernon smoker-34.117-5.444passive-25.845-5.6233.71123.051P-valuesactivenon smokernon smoker0.0047passive0.17610.31 In an investigation on the effect of cigarette smoking on cognitive ability,47 subjects were classified into 3 groups: those who had never smoked (non_smoker),those who were smokers but had not smoked for 24 hours (passive), and those whowere smokers and had been smoking in the 24 hours before the experiment (active).Subjects were then given a complex task to perform and scored for performanceon the task. We will use an analysis of variance (ANOVA) to determine whetherthere is a difference in mean performance score amongst the three levels of smokingstatus. An excerpt from the ANOVA results from iNZight is shown below:

Answered: Total number of observations: 47…

Total number of observations: 47 Inference of Performance Score by Smoker status: Group Means with 95% Confidence Intervals

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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