In a study of microplastics in our environment, it was determined that there are 5.25 trillion plastic pieces floating in the ocean,weighing more than 250,000 tons. In a recent expedition to examine whether increases in plastic production have led to changes inocean microplastics, 16 samples were taken at various locations in the Pacific Ocean. It was determined that the averageconcentration was 9.5 particles per liter of ocean water with a sample standard deviation of 6. In one of the earliest researchexpeditions to study microplastics in the ocean conducted in 2009, it was determined that the average concentration of microplasticswas 6 particles per liter (consider this the population or reference mean).What is the critical value for the two-tailed alternative hypothesis at alpha = 5%? (Hint: This is the value in the table that you willcompare your test statistic to in order to determine the outcome of the hypothesis test).2.1311.7462.1201.753

Method 1 : using t table From given data ,sample size is 16.Here population standard deviation not…

Answered: In a study of microplastics in our…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An article reports an investigation into the toxicity of bilirubin on several cell lines. Ten sets of human liver cells and 5 sets of mouse fibroblast cells were placed into solutions of bilirubin in albumin with a 1.4 bilirubin/albumin molar ratio for 24 hours. In the 10 sets of human liver cells, the average percentage of cells surviving was 53.9 with a standard deviation of 10.7. In the 5 sets of mouse fibroblast cells, the average percentage of cells surviving was 73.1 with a standard deviation of 9.1. Let μXμX represent the population mean for the mouse cells and let μYμY represent the population mean for the human cells. Find a 98% confidence interval for the difference μX−μYμX−μY . Round down the degrees of freedom to the nearest integer and round the answers to three decimal places. The 98% confidence interval is ( , ).
In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-shaped and has a mean of 40 and a standard deviation of 4. Using the empirical rule, what is the approximate percentage of daily phone calls numbering between 32 and 48?
Osteoporosis is a condition in which the bones become brittle due to loss of minerals. To diagnose osteoporosis, an elaborate apparatus measures bone mineral density (BMD). BMD is usually reported in standardized form. The standardization is based on a population of healthy young adults. The World Health Organization (WHO) criterion for osteoporosis is a BMD 2.5 standard deviations below the mean for young adults. BMD measurements in a population of people similar in age and sex roughly follow a Normal distribution. What percent of healthy young adults have osteoporosis by the WHO criterion? Give your answer to two decimal places.
Listed in the data table are amounts of strontium-90 (in millibrcquerels or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.10 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Find the test statistic, p value, and confidence interval
The piston diameter of a certain hand pump is 0.4 inch. The manager determines that the diameters are normally distributed, with a mean of 0.4 inch and a standard deviation of 0.006 inch. After recalibrating the production machine, the manager randomly selects 29 pistons and determines that the standard deviation is 0.0053 inch. Is there significant evidence for the manager to conclude that the standard deviation has decreased at the a = 0.05 level of significance? What are the correct hypotheses for this test? The null hypothesis is Ho: o = 0.006. The alternative hypothesis is H;: 0.006. Calculate the value of the test statistic. = 21.85 (Round to two decimal places as needed.) Use technology to determine the P-value for the test statistic. The P-value is (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. 1 part 1 remaining Clear All Check Answer
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
Concerns about climate change and CO2 reduction have limited the commercial production blends of biodiesel (from renewable sources) and petrodiesel (from fossil fuels). Random samples of 35 blended fuels are tested in a lab to ascertain the bio/total carbon ratio. If the true mean is 0.9480 with a standard deviation of 0.0060, within what interval will 95% of the sample means fall? What is the sampling distribution of x bar ? What theorem did you use to answer part (b)? What, if any, assumptions are necessary?
In a particular community, it is claimed that the mean household water usage for a particular month is 45 cubic meters. The following year, a countrywide water conservation campaign was conducted. Forty nine homes were randomly selected and found that the mean consumption is 54 cubic meters with a standard deviation of 5 cubic meters. Is there enough evidence to say that the mean household water usage per month is higher than 45 cubic meters at a = 0.01?
Example 2 : A drilling machine bores holes with a mean diameter of 0.5230 cm and a standard deviation of 0.0032 cm. Calculate the 2 - sigma and 3 - sigma upper and lower control limits for means of samples 4, and prepare a control chart.
Polychlorinated biphenyl (PCB) is among a group of organic pollutants found in a variety of products, such as coolants, insulating materials, and lubricants in electrical equipment. Disposal of items containing less than 50 parts per million (ppm) PCB is generally not regulated. A certain kind of small capacitor contains PCB with a mean of 47.7 ppm and a standard deviation of 5 ppm. The Environmental Protection Agency takes a random sample of 38 of these small capacitors, planning to regulate the disposal of such capacitors if the sample mean amount of PCB is 49.5 ppm or more. Find the probability that the disposal of such capacitors will be regulated. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Polychlorinated biphenyl (PCB) is among a group of organic pollutants found in a variety of products, such as coolants, insulating materials, and lubricants in electrical equipment. Disposal of items containing less than 50 parts per million (ppm) PCB is generally not regulated. A certain kind of small capacitor contains PCB with a mean of 48.2 ppm and a standard deviation of 5 ppm. The Environmental Protection Agency takes a random sample of 37 of these small capacitors, planning to regulate the disposal of such capacitors if the sample mean amount of PCB is 49.5 ppm or more. Find the probability that the disposal of such capacitors will be regulated. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
In a study on the physical activity of young adults, pediatric researchers measured overall physical activity as the total number of registered movements (counts) over a period of time and then computed the number of counts per minute (cpm) for each subject. The study revealed that the overall physical activity of obese young adults has a mean of μ = 325 cpm and a standard deviation of a = 90 cpm. In a random sample of n = 100 obese young adults, consider the sample mean counts per minute, x. Click the icon to view the table of normal curve areas. a. Describe the sampling distribution of x. Find μ. Find o-. X 0-= (Type an integer or a decimal.) Describe the shape of the sampling distribution of x. ✩ OA. Skewed right OB. Approximately normal OC. Skewed left b. What is the probability that the mean overall physical activity level of the sample is between 300 and 310 cpm? P(300 ≤x≤310) = (Round to four decimal places as needed.) c. What is the probability that the mean overall physical…

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