In a simple random sample of 170 households, the sample mean number of personal computers was 1.55. Assume the population standard deviation is σ=0.51. (a) Construct a 90% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 90% confidence interval for the mean number of personal computers is __<μ<__ . (b) If the sample size were 145 rather than 170, would the margin of error be larger or smaller than the result in part (a)? Explain. (c) If the confidence levels were 80% rather than 90%, would the margin of error be larger or smaller than the result in part (a)? Explain. (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1.09?
How many computers? In a simple random sample of 170 households, the sample
(a) Construct a 90% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 90% confidence interval for the mean number of personal computers is __<μ<__ .
(b) If the
(c) If the confidence levels were 80% rather than 90%, would the margin of error be larger or smaller than the result in part (a)? Explain.
(d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is less than 1.09?
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