In a series resistance-capacitance DC circuit, the instantaneous charge Q on the capacitor as a function of time (where t=0 is the moment the circuit is energized by closing a switch) is given by the equation Q(t)= CV (1- e-t/(RC)), where C, V, and R are constants. Further, the instantaneous charging current I, is the rate of change of charge on the capacitor, or l=dQ/ dt. a. Find the expression for I, as a function of time. b. If C=104 farads, R= 108 ohms, and V = 10 volts, what is the charging current after 150 seconds? (Hint: When placed into the function in part a the units can be combined into amps.) a. l = 0

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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In a series resistance-capacitance DC circuit, the instantaneous charge Q on the capacitor as a function of time (where t=0 is the moment the circuit is energized by closing a switch) is given by
the equation Q(t) = Cv (1-e -t/(RC)), where C, V, and R are constants. Further, the instantaneous charging current I, is the rate of change of charge on the capacitor, or l=dQ/dt.
a. Find the expression for I, as a function of time.
b. If C=104 farads, R= 108 ohms, and V = 10 volts, what is the charging current after 150 seconds? (Hint: When placed into the function in part a the units can be combined into amps.)
a. l = 0
Transcribed Image Text:In a series resistance-capacitance DC circuit, the instantaneous charge Q on the capacitor as a function of time (where t=0 is the moment the circuit is energized by closing a switch) is given by the equation Q(t) = Cv (1-e -t/(RC)), where C, V, and R are constants. Further, the instantaneous charging current I, is the rate of change of charge on the capacitor, or l=dQ/dt. a. Find the expression for I, as a function of time. b. If C=104 farads, R= 108 ohms, and V = 10 volts, what is the charging current after 150 seconds? (Hint: When placed into the function in part a the units can be combined into amps.) a. l = 0
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