A projectile is fired straight up from a platform 10ft above the ground, with an initial velocity of 160 ft/sec. Assume that the only force affecting the motion of the projectile during its flight is from gravity, which produces a downward acceleration of 32 ft/sec². What is the equation for the height of the projectile above the ground as a function of time t if t = 0 when the projectile is fired? s = -16t² + 80t + 10 s = 16t2 – 160t + 10 O D A s = -16t2 – 160t + 10 s = -16t2 + 160t + 10 O B

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