An object of mass 5 kg is released from rest 3000 m above the ground and allowed to fall under the influence of gravity. Assuming the force due to air resistance is proportional to the velocity of the object with proportionality constant b = 50 N-sec/m, determine the equation of motion of the object. When will the object strike the ground? Assume that the acceleration due to gravity is 9.81 m/sec² and let x(t) represent the distance the object has fallen in t seconds.

Q: Suppose an object is moving along a line such that the acceleration after t seconds is 6t -8t…

A:

Q: A stone is thrown vertically upwards, from the edge of a 5 m tall cliff with an initial velocity of…

A:

Q: 1 mdv dt 10 dv dt = mg-bv; v(0) = v = (10) (9.81)-50 v

A: mdvdt=mg-bv, v0=v10dvdt=109.81-50v, v0=0

Q: An object is moving with the velocity v(t) = 5/ sqrt of t  cm/sec. At time t = 4 sec, its position…

A: As we know

Q: A comet passing by a star, with initial velocity (30, 60), experiences a force which causes it to…

A:

Q: A trough is 5 meters long and 1 meter high. The vertical cross-section of the trough parallel to an…

A: To find the work required to empty the trough, you can use the principles of calculus and fluid…