In a recent questionnaire about home ownership, a random sample of 545 homeowners were asked about fixed and adjustable rate mortgages, and 268 reported that they have an adjustable rate mortgage. What value of z should be used to calculate a confidence interval with a 95% confidence level? ζ0.10 Ζ0.05 Ζ0.025 Ζ0.01 Ζ0.005 1.282 1.645 1.960 2.326 2.576 Provide your answer below:
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- Pain after surgery: In a random sample of 60 patients undergoing a standard surgical procedure, 16 required medication for postoperative pain. In a random sample of 80 patients undergoing a new procedure, only 14 required pain medication. Part: 0 / 2 Part 1 of 2 (a) Construct a 99.9% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p, denote the proportion of patients who had the old procedure needing pain medication. Use tables to find the critical value and round the answer to at least three decimal places. A 99.9% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures isA survey asked senior executives at large corporations their opinions about the economic outlook for the future. One question was, "Do you think that there will be an increase in the number of full- time employees at your company over the next 12 months?" In the current survey, 232 of 400 executives answered Yes, while in a previous year survey, 184 of 400 executives had answered Yes. Provide a 95% confidence interval estimate for the difference between the proportions at the two points in time. (Use current year previous year. Round your answer to four decimal places.) to What is your interpretation of the interval estimate? The 95% confidence interval ---Select--- ✓zero. This suggests that the proportion of executives who are predicting an increase in full-time jobs for the current year is ---Select---] than the proportion of executives who were predicting an increase in full-time jobs for the previous year.In a recent questionnaire about homeownership, a random sample of 545 homeowners were asked about fixed and adjustable-rate mortgages, and 268 reported that they have an adjustable-rate mortgage. What value of z should be used to calculate a confidence interval with a 95% confidence level? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576Pain after surgery: In a random sample of 42 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 90 patients undergoing a new procedure, only 11 required pain medication. Part: 0 / 2 Part 1 of 2 (a) Construct a 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p, denote the proportion of patients who had the old procedure needing pain medication. Use tables to find the critical value and 1 round the answer to at least three decimal places. A 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures isRepeat the analysis of the clinical study in Example 4.4.8 on page 155 using a confidence level of 95%. What conclusion can you draw about the effectiveness of the drug?Find the 95% confidence interval for the percentage of leaky diapers in Example 4.4.4 assuming 400 diapers were tested and 20% were leaky. Note that it is 8 percentage points long.A newsgroup is interested in constructing a 90% confidence interval for the difference in the proportions of Texans and New Yorkers who favor a new Green initiative. Of the 531 randomly selected Texans surveyed, 354 were in favor of the initiative and of the 559 randomly selected New Yorkers surveyed, 460 were in favor of the initiative. a. With 90% confidence the difference in the proportions of Texans and New Yorkers who favor a new (round to 3 decimal places) and (round to 3 decimal Green initiative is between places). b. If many groups of 531 randomly selected Texans and 559 randomly selected New Yorkers were surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of the difference in the proportions of Texans and New Yorkers who favor a new Green initiative and about percent will not contain the true population difference in proportions.Assume that last year in a particular state there were 211 children out of 1990 who were diagnosed with Autism Spectrum Disorder. Nationally, 1 out of 88 children are diagnosed with ASD. It is believed that the incident of ASD is more common in that state than nationally. Calculate a 96% confidence interval for the percentage of children in that state diagnosed with ASD.P: Parameter What is the correct parameter symbol for this problem? What is the wording of the parameter in the context of this problem? A: Assumptions Since information was collected from each object, what conditions do we need to check? Check all that apply. n≥30n≥30 or normal population. N≥20nN≥20n n(pˆ)≥10n(p̂)≥10 σσ is known. σσ is unknown. n(1−pˆ)≥10n(1-p̂)≥10 Check those assumptions: 1. nˆpnp^= which is 2. n(1−ˆp)n(1-p^)= which is 3. NN= which is If no N is given in the problem, use 1000000N: Name the procedure The…1Pain after surgery: In a random sample of 54 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 94 patients undergoing a new procedure, only 16 required pain medication. Part: 0/ 2 Part 1 of 2 (a) Construct a 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p, denote the proportion of patients who had the old procedure needing pain medication. OL Use tables to find the critical value and round the answer to at least three decimal places. A 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures is9.2.3In a clinical trial, 50 patients who received a new medication are randomly selected. It was found that 10 of them suffered serious side effects from this new medication. Let p denote the population proportion of patients suffered serious side effects from this new medication. Find a point estimate for p. Construct a 95% confidence interval for p: ( ). (Write down all the digits you have from calculator)SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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