In a random sample of five mobile devices, the mean repair cost was $65.00 and the standard deviation was $12.00. Assume the population is normally distributed and use at-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results.The 95% confidence interval for the population mean p is (50.1,79.9).(Round to two decimal places as needed)ly CoursesCourse HomeThe margin of error is $(Round to two decimal places as needed.)AssignmentsGradebookChapter ContentsеТеxtMultimedia LibraryStudy PlanTools for SuccessAccessible ResourcesSkills for SuccessClear allCheck answerHelp me solve thisView an exampleGet more help -Media -Pearson2:34 PM57°F12/1/2021OType here to searchCE-F1PriScDeleteEDInsertF6F7F8F10F12&Backspaceనుంగా38.WEU1P%3D

Given: n= 5.0 , x̄= 65.0 s= 12.0 degree of freedom=n-1= 4.0 At 95.0 % confidence level with d.o.f.=…

Answered: In a random sample of five mobile…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A statistics practitioner took a random sample of 42 observations from a population whose standard deviation is 30 and computed the sample mean to be 102. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =
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tion. Use this information to construct the 90% and 95% confidence intervals fc of the confidence intervals. ce of a certain stock was $123.13. Assume the population standard deviation is
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