A statistics practitioner took a random sample of 48 observations from a population whose standard deviation is 32 and computed the sample mean to be 107. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =

Q: Of 500 random people surveyed, 72 were smokers.  Find the 95% confidence interval. SE=0.0157

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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean.   A…

A: The confidence interval in terms of sample mean and margin of error is defined as (x̅ ± ME), where…

Q: Jse the confidence interval to find the estimated margin of error. Then find the sample mean. A…

A: Solution: The given confidence interval is ( 3.0, 3.6) Lower limit= 3.0 Upper limit= 3.6

Q: Use the confidence interval to find the margin of error and the sample mean. (0.498,0.640) The…

A: Confidence interval is 0.498, 0.640 To find :  (i) margin of error (ii) sample mean Margin of error…

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean.   A…

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Q: Suppose you select a random sample of N=81, and find X = 50, and s = 9.9. Determine the 99%…

A: Given Mean=50 Standard deviations=9.9 n=81

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean.   A…

A: It is given that, the confidence interval is (4.4, 5.4).

Q: 3. needed to estimate the percentage of adults who can touch their nose with Find the sample size…

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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean.   A…

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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…

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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…

A: A confidence interval of population mean, µ, in terms of sample mean and margin of error, can be…

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A: 1. The conditions for using t-distribution are: Sample size is small. Population standard deviation…

Q: A random sample of 600 adults in Flagstaff found 90 adults who had lost a job in the past year. Find…

A: Step 1:Given data : Sample size n=600no. of successes x=90   Sample proportion p^​=60090​=0.15Let p…

Q: find the margin of error of a 99% confidence interval for the mean score of all student

A: It is given that  Sample mean = 93 Sample standard deviation, s = 7 Sample size, n = 30

Q: Use the confidence interval to find the margin of error and the sample mean. (0.392,0.490) The…

A: Given that, The confidence interval is 0.392, 0.490

Q: Use the confidence interval to find the margin of error and the sample mean.   (0.056,0.180)…

A: Given confidence interval  (0.056,0.180) calculate Margin of error and sample mean

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…

A: Given confidence interval is (3.1, 3.7) We have to find the Margin of error and mean. We know that…

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A: Obtain the 98% confidence interval for the population mean. The 98% confidence interval for the…

Q: se the confidence interval to find the margin of error and the sample mean. (0.458,0.600) he margin…

A: The given confidence interval is (0.458,0.600)

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Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean.   A…

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Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?

Q: Use the confidence interval to find the margin of error and the sample mean. (0.328,0.430) The…

A: Given data,Lower limit=0.328Upper limit=0.430

Q: The average and standard deviation for ACT scores are 20 and 3 respectively. average and standard…

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Q: If n = 330 and X = 264, construct a 95% confidence interval for the population proportion, p.

A: Ans#- From the provided information, Confidence level = 95% Sample size (n) = 330, x = 264 Sample…

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A: The margin of error for each confidence interval (E) is obtained as follows:

Q: Use the confidence interval to find the margin of error and the sample mean. (0.278,0.400) The…

A: We have given the confidence interval(0.278, 0.400)Lower limit = 0.278Upper limit = 0.400

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean.   A…

A:

Q: Use the confidence interval to find the margin of error and the sample mean. (0.186,0.350) The…

A: Solution: From the given information, the confidence interval is (0.186, 0.350).

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…

A: Given, A biologist reports a confidence interval (1.7,2.9 ) of when estimating the mean height​ (in…

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…

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Q: . A survey of folk music fans yields this 95% confidence interval estimate of the proportion of fans…

A: The 95% confidence interval for proportion of fans who love music of David Wilcox is 0.74 to 0.86

Q: Use the confidence interval to find the margin of error and the sample mean.   (0.676,0.800)

A: The margin of error is the most common term which we use in a confidence interval. It is the degree…

Q: Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from…

A: Given regression equation is y=-107+1.03x If x=184 y=?

Q: 6) Find the t, value from Table for the indicated confidence level and sample size. 95% confidence…

A: a) 95% confidence level and n = 35 Degree of freedom = 35 – 1 = 34 Significance level(α) = 1-0.95 =…

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A: From the provided information, Sample size (n) = 8

Q: If n = 440 and X = 352, construct a 90% confidence interval for the population proportion, p. Give…

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Q: Explain how In mean or proportion. Choose the correct answer below. ation vanance is mere om linding…

A: Here, Given that confidence interval for variance and confidence interval for mean or proportion.

Q: Mark each statement TRUE or FALSE. For these problems, assume that to estimate average time spent…

A: It is given that the sample size is 10.

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…

A: Margin of error is 0.4 Sample mean is 2.7Explanation:

Q: Use the confidence interval to find the estimated margin of error. Then find the sample mean. A…

A: To find the estimated margin of error and sample mean from the given confidence interval (2.3, 3.3)…

Q: statistics practitioner took a random sample of 48 observations from a population whose standard…

A: We have given that  Sample mean =100 Population standard deviation =23 Sample size n =48

Q: The estimated margin of error is The sample mean is

A: Given that,The Confidence interval for the population mean is (1.9, 3.1).Lower limit Upper limit