In a study of statistics professors' salaries (USA) the following data was obtained:n = 23, ī = $100000, s = $12500Determine the 95% confidence interval for standard deviation (o) of the population.You may assume the population is normally distributed.Confidence Interval: ($$4Enter numbers correct to one unit. A sample of 19 Math SAT scores for women was collected. The mean score for the sample was 496 and the sample standard deviation was 115.Find the 95% confidence interval for the population mean µ. Assume the population has a normal distribution.Confidence Interval: (Enter numbers correct to one unit.

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Answered: In a study of statistics professors'…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which one of the following statements about confidence intervals is false? Given the same sample of data, a 99% confidence interval will be wider than a 95% confidence interval. The size of the population affects the width of a confidence interval. The sample statistic determines the center of the confidence interval. The value of z* affects the width of a confidence interval. The general format of a confidence interval is “sample statistic ± margin of error.”
A statistics practitioner took a random sample of 59 observations from a population whose standard deviation is 32 and computed the sample mean to be 95. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval= C. Estimate the population mean with 99% confidence. Confidence Interval=
You sample 36 students to find out how many hours they spent online last week. Your sample mean is 54. The population standard deviation, sigma, is 8.2. Your client now wants the 90% confidence interval for this sample mean. It is: 40.1 to 67.9 51.8 to 56.2 40.5 to 67.5 51.0 to 56.0
A statistics practitioner took a random sample of 43 observations from a population whose standard deviation is 30 and computed the sample mean to be 109. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =
You measure 38 dogs' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 5.6 ounces. Based on this, construct a 99% confidence interval for the true population mean dog weight. Round Iyour answers to two decimal places. <με Enter an integer or decimal number [more..
you measure the weights of a random sample of twenty-five people. The sample mean is 60 kg. Suppose that the mean weights of people follow a normal distribution with an unknown mean and standard deviation of 5 kg. You compute a 95% confidence interval for μ. The 95% confidence interval for μ is?
What is the value of SS (sum of squared deviations) for the following set of scores? If the scores constitute a population, what is the population standard deviation, s? Scores: 1, 1, 4, 0.
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
the population You measure 27 dogs' weights, and find they have a mean weight of 58 ounces. standard deviation is 7 ounces. Based on this, construct a 95% confidence interval for the true population mean dog weight. Give your answers as decimals, to two places - ounces Enter an integer or decimal number [more..]
A professor was curious about her students' grade point averages. She took a random sample of 15 students and found a mean GPA of 3.01 with a standard deviation of 0.534. Which of the following formulas gives a 99% confidence interval for the mean GPA of the professor's students?
A survey of amount of money (in £) spent on takeaway orders in a seaside town is conducted. The survey results which are based on a random sample of 100 households, found the mean monthly expenditure of £70.2 and the standard deviation £20.2. What statement can you make about the mean expenditure of all household in the town using: A 95 % confidence interval A 99.5 % confidence interval Provide an interpretation of your results in (a) and (b).
The accompanying table shows data for the weights of backpacks for men and women. Assume that the data are from random samples and the distributions are Normal. Complete parts (a) and (b) below. E Click the icon to view the data table. a. Find a 95% confidence interval for the difference between means HFemale - HMale state whether it captures 0, and explain what that shows about the mean. The 95% confidence interval is ( D (Round to two decimal places as needed. Use ascending order.) Backpack weights Female Male 10 10 12 8 9. 7 5 10 7 20 3 11 8 14 13 11 14 6 7 22 11 12 15 10 17 22 10 7 25 11 7 15 11 11 4 16 13 20 21 15 10 9. 16 10 15 13 10 10 17 12 11 38 6. 6. 7 19 12 13 20 8 14 15 18 19 10 16 16 13 18 12 14 13 13 15 14 14 7 7 14 13 27 11

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