In a random sample of 375 students at a university, 307 stated that they were nonsmokers. Based on thconfidence interval for the proportion of all students at the university who are nonsmokers. Then find the90% confidence interval.Carry your intermediate computations to at least three decimal places. Round your answers to two decimof formulas.)Lower limit:Upper limit:XŚ ersity, 307 stated that they were nonsmokers. Based on this sample, compute a 90%lents at the university who are nonsmokers. Then find the lower limit and upper limit of thest three decimal places. Round your answers to two decimal places. (If necessary, consult a list=

Answered: Image /qna-images/answer/e3853820-098e-4bcd-a4b1-46d13080c9c6.jpg

Answered: In a random sample of 375 students at a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average American gets a haircut every 34 days. Is the average smaller for college students? The data below shows the results of a survey of 15 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 23, 32, 38, 31, 39, 35, 25, 30, 36, 40, 27, 23, 32, 25 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv Hi: ?vSelect an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is 2v a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that.. O The data suggest the population mean is not significantly lower than 34 at a = 0.10, so there M 24 3. 4. 5 6. 7 EU
suppose that a category of world-class runners are known to run a marathon (26 miles) in an average of 143 minutes with a standard deviation of 14 minutes. consider 49 of the races. Let x̅ = the average of the 49 races. I need help finding the median of the average running times. if someone could explain how to solve this problem that would be great
Assume that adults have IQ scores that are normally distributed with a mean of 95.2, and a standard deviation of 22.2 Find the first quartile Q1, which is the IQ score separating the bottom 25% from the top 75%. Can you please provide step by step using the T1-84 plus calculator. I keep getting stuck on locating the z-score. I know the first Q is .25 If you use the formula, please provide the actual figures including a picture- so I have a well-rounded answer to this question. Thank you
The arm span of a team of athletes was measured and listed in the attached image (Problem-Image2.jpg). a) Calculate the mean arm span, ?̄. b) Complete the table and calculate (to two decimal places of accuracy, the standard deviationof the data.). Check the equation in the attached image (Problem-Image3.jpg)
Among 157 Cuban American men ,the mean systolic blood pressure was 146 mm Hg with a standard deviation of 27. We wish to know if based on these data, we may conclude that the mean systolic blood pressure for a population of Cuban American is greater than 140. Use α=0.01 (solve without excel) , show work
A student takes a true-false test that has 10 questions and guesses randomly at each answer. LetX be the number of questions answered correctly. c)The mean and stand deviation of X (show work and round final answer to 2 decimal places) Mean: Standard deviation =
Ginny’s professors conspired to all give a test on the same day. She gets an 82 on her psychology exam with μ = 76 and σ = 12. She receives a z-score of -.25 on her management exam. Finally, she scored at the 50th percentile on her normally distributed math exam. Place her test scores in order from lowest to highest score.
Assume that we have made 10 repeated measurements of a quantity, and as a result the error assigned to the “best estimate” of the mean is 6. If we then expand our data set to a total of 20 measurements, the error in the mean will reduce to just 3. True or False

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