| Suppose that the readings on the thermometers are normally distributed with a mean of 0° and a standard deviation of 1.00°C. If 5% of the thermometers are rejected because they have readings that are too high, but all other thermometers are acceptable, find the reading that separates the rejected thermometers from the others.

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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**Problem Statement:**

Suppose that the readings on the thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. If 5% of the thermometers are rejected because they have readings that are too high, but all other thermometers are acceptable, find the reading that separates the rejected thermometers from the others.

**Solution:**

To find the temperature that separates the top 5% of thermometer readings (those that are too high and therefore rejected), we need to determine the 95th percentile of the normal distribution. The percentile can be found using the properties of the normal distribution.

Since the mean (μ) is 0°C and the standard deviation (σ) is 1.00°C, we can use the standard normal distribution table or a calculator to find the Z-score that corresponds to the 95th percentile.

Once the Z-score is found, the corresponding thermometer reading can be calculated using the formula:

\[ X = μ + Z \times σ \]

Where:
- \( X \) is the thermometer reading.
- \( μ \) is the mean (0°C).
- \( Z \) is the Z-score for the 95th percentile.
- \( σ \) is the standard deviation (1.00°C).

This calculation will give the temperature reading that separates the acceptable thermometer readings from the ones that are rejected.
Transcribed Image Text:**Problem Statement:** Suppose that the readings on the thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. If 5% of the thermometers are rejected because they have readings that are too high, but all other thermometers are acceptable, find the reading that separates the rejected thermometers from the others. **Solution:** To find the temperature that separates the top 5% of thermometer readings (those that are too high and therefore rejected), we need to determine the 95th percentile of the normal distribution. The percentile can be found using the properties of the normal distribution. Since the mean (μ) is 0°C and the standard deviation (σ) is 1.00°C, we can use the standard normal distribution table or a calculator to find the Z-score that corresponds to the 95th percentile. Once the Z-score is found, the corresponding thermometer reading can be calculated using the formula: \[ X = μ + Z \times σ \] Where: - \( X \) is the thermometer reading. - \( μ \) is the mean (0°C). - \( Z \) is the Z-score for the 95th percentile. - \( σ \) is the standard deviation (1.00°C). This calculation will give the temperature reading that separates the acceptable thermometer readings from the ones that are rejected.
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