Raw scores on standardized tests are often transformed for easier comparison. A test of Math ability has a Mean of 153 and a Standard Deviation of 10 when given to 3rd-graders. While 6th-graders have a Mean of 164 and a Standard Deviation of 7 on the same test. Leslie is a 3rd-grade student who scores 159 on the test. Hollis is a 6th-grade student who scores 168 on the test. Calculate the z-score for each student. Who scored higher within their grade-level?
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
 alt="Title: Understanding Z-Scores in Standardized Testing
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**Text:**
Raw scores on standardized tests are often transformed for easier comparison. A test of Math ability has a mean of 153 and a standard deviation of 10 when given to 3rd-graders. While 6th-graders have a mean of 164 and a standard deviation of 7 on the same test.
Leslie is a 3rd-grade student who scores 159 on the test.
Hollis is a 6th-grade student who scores 168 on the test.
Calculate the z-score for each student.
Who scored higher within their grade-level?
- ○ Hollis; because her z-score is closer to the mean for 6th-graders than Leslie's is for 3rd-graders.
- ● Leslie; because her z-score is larger than Hollis' z-score.
- ○ Leslie; because she is almost as smart as Hollis.
- ○ Hollis; because 168 is higher than Leslie's 159.
- ○ Leslie; because she is 6 points higher than the 3rd-grade level mean while Hollis is only 4 points higher than the 6th-grade level mean.
**Explanation:**
To determine who scored higher within their grade level, calculate the z-score for each student. The z-score is found by subtracting the mean from the score and then dividing by the standard deviation.
For Leslie (3rd-grade):
- Z = (159 - 153) / 10 = 0.6
For Hollis (6th-grade):
- Z = (168 - 164) / 7 = 0.57
Since Leslie's z-score (0.6) is larger than Hollis' (0.57), Leslie scored higher within her grade level.
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