In a random sample of 100 adults, 27 say they are in favor of outlawing cigarettes. Let p be the proportion of all adults who are in favor of outlawing cigarettes. A researcher wishes to test the following hypotheses: Ho : p = 0.23; Ha :p#0.23. In this scenario, the appropriate test statistic is: p-Po (a) Z = V Po90/n * - Ho (b) Z || 8//n | (c) T = 8/Vn p-Po (d) Z = VPâ/n
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- According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 320 community college students at random and finds that 135 of them have a smart phone. In testing the hypotheses: Ho: p = 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4. 1. This is an example of a hypothesis test. 2. Find the standard error. 3. Find the z value. 4. Find the p-value. 5. The communication professor should the null hypothesis.A random sample of n1 = 157 people ages 16 to 19 were taken from the island of Oahu, Hawaii, and 12 were found to be high school dropouts. Another random sample of n2 = 129 people ages 16 to 19 were taken from Sweetwater County, Wyoming, and 6 were found to be high school dropouts. Do these data indicate that the population proportion of high school dropouts on Oahu is different (either way) from that of Sweetwater County? Use a 1% level of significance. (a) What is the level of significance? What is the value of the sample test statistic? (Test the difference p1 − p2. Do not use rounded values. Round your final answer to two decimal places.) (c) Find (or estimate) the P-value. (Round your answer to four decimal places.)A recent study of 1000 high school juniors and seniors asked whether or not they felt smartphones are a valuable learning tool. Additional data were gathered on their smartphone plan (unlimited data, additional texting, or standard voice plan) and which class they were in (junior vs. senior). Which of the following is a correct pair of hypotheses the researchers could test? (A) Ho: The proportion of juniors and seniors who feel smartphones are a valuable learning tool is the same for students that have each type of plan. Ha: The proportion of juniors and seniors who feel smartphones are a valuable learning tool is not the same for students that have each type of plan (B) Ho: The proportion of students who feel smartphones are a valuable learning tool is the same for students that have each type of plan. Ha: The proportion of students who feel smartphones are a valuable learning tool is not the same for students that have each type of plan. (C) Ho: There is an association between class…
- A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 80%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 80% of married couples. In a random sample of 215 married couples who completed her program, 180 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. A. State the null hypothesis Hoand the alternative hypothesis H1. Ho: H1: B. Find the value of the test statistic. (Round to three or more decimal places.) C. Find the critical value. (Round to three or more decimal places.) D. Is there enough evidence to support the marriage counselor's claim that the proportion of married couples for whom her program…A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 79%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 79% of married couples. In a random sample of 250 married couples who completed her program, 205 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₂ : D H₁ : 0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 77%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 77% of married couples. In a random sample of 215 married couples who completed her program, 167 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H0 and the alternative hypothesis H1. H0: H1: (b) Determine the type of test statistic to use. ▼(Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three…
- A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.Males and females were asked what they would do if they received a $100 bill in the mail that was addressed to their neighbor, but had been incorrectly delivered to them. Of the 70 males sampled, 55 said yes they would return it to their neighbor. Of the 130 females sampled, 120 said yes. The overall question is: Is this sufficient evidence to say that the two true proportions are different? Assume that the p-value turns out to be .027 (again not the correct p-value for this situation but use it to answer this question). What is your decision on this hypothesis test using a 5% level of significance? O Fail to reject the null hypothesis Reject the null hypothesisanswer the second question.
- According to a Pew Research Center study, in May 2011, 33% of all American adults had a smart phone (one which the user can use to read email and surf the Internet). A communications professor at a university believes this percentage is higher among community college students. She selects 323 community college students at random and finds that 134 of them have a smart phone. In testing the hypotheses: Ho: p= 0.33 versus Ha: p > 0.33 Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for # 3 and #4. 1. I 4. Find the p-value.-- 5. The communication professor should the null hypothesis.A survey is conducted to determine if there is a difference in the proportion of students, parents, and teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the tables. Observed counts: Expected counts: The researcher would like to test these hypotheses: H0: There is no difference in the distribution of responses among these three populations.Ha: There is a difference in the distribution of responses among these three populations. The conditions for inference are met. What is the value of the chi-square test statistic and what are the degrees of freedom for this test? χ‑2 = 0.19, df = 2χ‑2 = 0.19, df = 5χ‑2 = 0.44, df = 2χ‑2 = 0.44, df = 5A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 75%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 75% of married couples. In a random sample of 245 married couples who completed her program, 185 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.01 level of significance? (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) H₁ (b) Determine the type of test statistic to use. (Choose one) ▼ (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) (e) Is there enough…