In a particular photoelectric experiment, a stopping potential of 2.1 V is measured when ultraviolet light with a wavelength of 290 nm is incident on a metal. Given the light of speed c = 3.0 × 10® m/s and Planck constant h = 6.625 x 10-34 J. s or 4.14 × 10-15 eV.s (a) Describe and illustrate the photoelectric experiment and explain why it cannot be explained by classical physics. (b) Using the same setup and metal, determine the stopping potential if blue light with a wavelength of 440 nm is used, instead of the ultraviolet light. (c) Using the same setup and metal, describe what happened if a red light with a wavelength of 620 nm is used, instead of the ultraviolet light.

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In a particular photoelectric experiment, a stopping potential of 2.1 V is measured when
ultraviolet light with a wavelength of 290 nm is incident on a metal. Given the light of speed
c = 3.0 x 108 m/s and Planck constant h = 6.625 x 10-34 J. s or 4.14 × 10-15 eV.s
%3D
(a) Describe and illustrate the photoelectric experiment and explain why it cannot be
explained by classical physics.
(b) Using the same setup and metal, determine the stopping potential if blue light with a
wavelength of 440 nm is used, instead of the ultraviolet light.
(c) Using the same setup and metal, describe what happened if a red light with a wavelength
of 620 nm is used, instead of the ultraviolet light.
Transcribed Image Text:In a particular photoelectric experiment, a stopping potential of 2.1 V is measured when ultraviolet light with a wavelength of 290 nm is incident on a metal. Given the light of speed c = 3.0 x 108 m/s and Planck constant h = 6.625 x 10-34 J. s or 4.14 × 10-15 eV.s %3D (a) Describe and illustrate the photoelectric experiment and explain why it cannot be explained by classical physics. (b) Using the same setup and metal, determine the stopping potential if blue light with a wavelength of 440 nm is used, instead of the ultraviolet light. (c) Using the same setup and metal, describe what happened if a red light with a wavelength of 620 nm is used, instead of the ultraviolet light.
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