In a one-tailed test of hypothesis of the population mean, with a 5% level of significance and a sample of 21 taken from a normally distributed population where the standard deviation is not known, determine the critical value of the test statistic.
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In a one-tailed test of hypothesis of the population mean, with a 5% level of significance and a sample of 21 taken from a
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- Among private universities in the United States, the mean ratio of students to professors is 35.2 (i.e., 35.2 students for each professor) with a standard deviation of 8.8. Suppose a random sample of 50 universities is selected and the observed mean student-to-professor ratio is 38. Is there evidence that the reported mean ratio actually exceeds 35.2? Use = 0.05 and conduct the appropriate hypothesis test. ( See attached picture )A coin-operated drink machine was designed to discharge a mean of 8 ounces of coffee per cup. In a test of the machine, the discharge amounts in 16 randomly chosen cups of coffee from the machine were recorded. The sample mean and sample standard deviation were 7.97 ounces and 0.24 ounces, respectively. If we assume that the discharge amounts are normally distributed, is there enough evidence, at the 0.1 level of significance, to conclude that the true mean discharge, µ, differs from 8 ounces? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H,. p H, :0 Hị :0 (b) Determine the type of test statistic to use. (Choose one) ▼ O=0 OSO O20 |(c) Find the value of the test statistic. (Round to three or more decimal places.) OBig babies: The National Health Statistics Reports described a study in which a sample of 310 one-year-old baby boys were weighed. Their mean weight was 24.4 pounds with standard deviation 5.3 pounds. A pediatrician claims that the mean weight of one-year-old boys is greater than 25 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the α = 0.10 level of significance and the P-value method with the TI-84 Plus calculator. Compute the P-value. Round the answer to at least four decimal places. P-value = ____ How do I solve this problem using the TI-84 calculator?Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenHistorically, evening long-distance calls from a particular city have averaged 15.1 minutes per call. In a random sample of 37 calls, the sample mean time was 13.3 minutes. Assume the standard deviation is known to be 5 minutes. Using a 0.05 level of significance, is there sufficient evidence to conclude that the average evening long-distance call has decreased?For an upper-tail test at the 1% significance level, what is the appropriate critical value when a sample of size 28 is drawn from a normal population with unknown standard deviation?Small-business telephone users were surveyed 6 months after access to carriers other than Carrier A became available for wide-area telephone service. Of a random sample of 240 Carrier A users, 135 said they were attempting to learn more about their options, as did 227 of an independent random sample of 260 users of alternate carriers. Test, at the 1% significance level against a two-sided alternative, the null hypothesis that the two population proportions are the same. Click the link to view a standard normal distribution table. be the Let Px be the proportion of Carrier A users who said they were attempting to learn more about their options and Py proportion of users of alternate carriers who said they were attempting to learn more about their options. Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Px-Py=0 H₁: Px-Py 20 O D. Ho: Px-P₁ #0 H₁: Px - Py = 0 B. Ho: Px-Py = 0 H₁: Px-Py 0Is there any difference in the variability in golf scores for players on the LPGA Tour (the women's professional golf tour) and players on the PGA Tour (the men's professional golf tour)? A sample of 20 tournament scores from LPGA events showed a standard deviation of 2.4623 strokes, and a sample of 30 tournament scores from PGA events showed a standard deviation of 2.2118. Conduct a hypothesis test for equal population variances to determine whether there is any statistically significant difference in the variability of golf scores for male and female professional golfers. Use a = = 0.10. Ho : o Ha : o - Select your answer - - Select your answer What is your conclusion? There is - Select your answer V significant difference in the variances. - Select your answer -A coin-operated drink machine was designed to discharge a mean of 8 ounces of coffee per cup. In a test of the machine, the discharge amounts in 20 randomly chosen cups of coffee from the machine were recorded. The sample mean and sample standard deviation were 8.14 ounces and 0.23 ounces, respectively. If we assume that the discharge amounts are normally distributed, is there enough evidence, at the 0.05 level of significance, to conclude that the true mean discharge, μ , differs from 8 ounces? Perform a two-tailed test. Then fill in the table below. Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. The null hypothesis: H0: The alternative hypothesis: H1: The type of test statistic: (Choose one)ZtChi squareF The value of the test statistic:(Round to at least three decimal places.) The two critical values at the 0.05 level…IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. A charter school wants to know if their students have an average IQ that is higher than the population average. They take a random sample of 25 students and find a mean IQ of 108 with a standard deviation of 21. Use a 5% significance level. What is the P value with work? Do we reject the null hypothesis in this case? What does the hypothesis test say about the mean pulse rate.A researcher wishes to test whether the mean of a normally distributed population is greater than 1.06 at the 5% significance level. Based upon 22 independent observations, she observes a sample mean of 1.77 and a sample standard deviation of 0.84. Determine the degrees of freedom of the null distribution of Student's t test.A coin- ed drink machine was designed to discharge a mean of 7 ounces of coffee per cup. In a test of the machine, the discharge amounts in 13 randomly chosen cups of coffee from the machine were recorded. The sample mean and sample standard deviation were 6.96 ounces and 0.14 ounces, respectively. If we assume that the discharge amounts are normally distributed, is there enough evidence, at the 0.1 level of significance, to conclude that the true mean discharge, u, differs from 7 ounces? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H,. p H, :0 H :0 (b) Determine the type of test statistic to use. (Choose one) ▼ D=0 OSO (c) Find the value of the test statistic. (Round to three or more decimal places.) OSEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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