In a nuclear fission reaction a heavy nucleus divides to form smaller nuclei and one or more neutrons. Many nuclei can undergo fission, but the fission reactions of uranium-235 and plutonium-239 are the principal ones that generate energy in nuclear power plants. This problem deals with balancing the fission reaction of the uranium-235 isotope as it undergoes bombardment from a neutron. Part A When a 235 U nucleus is bombarded by neutrons (n) it undergoes a fission reaction, resulting in the formation of two new nuclei and neutrons. The following equation is an example of one such fission process: 2U+n+Ba+ Kr +3n Enter the isotope symbol for the barium (Ba) nucleus in this reaction. Express your answer as an isotope. ► View Available Hint(s) _ | ΑΣΦ A chemical reaction does not occur for this question. Submit Part B ? In another process in which 235 U undergoes neutron bombardment, the following reaction occurs: 25U+nSr +54 Xe + 3n Enter the isotope symbol for the strontium (Sr) nucleus in this reaction. Express your answer as an isotope. ►View Available Hint(s) °= | ΑΣΦ ? A chemical reaction does not occur for this question.
In a nuclear fission reaction a heavy nucleus divides to form smaller nuclei and one or more neutrons. Many nuclei can undergo fission, but the fission reactions of uranium-235 and plutonium-239 are the principal ones that generate energy in nuclear power plants. This problem deals with balancing the fission reaction of the uranium-235 isotope as it undergoes bombardment from a neutron. Part A When a 235 U nucleus is bombarded by neutrons (n) it undergoes a fission reaction, resulting in the formation of two new nuclei and neutrons. The following equation is an example of one such fission process: 2U+n+Ba+ Kr +3n Enter the isotope symbol for the barium (Ba) nucleus in this reaction. Express your answer as an isotope. ► View Available Hint(s) _ | ΑΣΦ A chemical reaction does not occur for this question. Submit Part B ? In another process in which 235 U undergoes neutron bombardment, the following reaction occurs: 25U+nSr +54 Xe + 3n Enter the isotope symbol for the strontium (Sr) nucleus in this reaction. Express your answer as an isotope. ►View Available Hint(s) °= | ΑΣΦ ? A chemical reaction does not occur for this question.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:In a nuclear fission reaction a heavy nucleus divides to
form smaller nuclei and one or more neutrons. Many
nuclei can undergo fission, but the fission reactions of
uranium-235 and plutonium-239 are the principal ones
that generate energy in nuclear power plants. This
problem deals with balancing the fission reaction of the
uranium-235 isotope as it undergoes bombardment
from a neutron.
Part A
When a 23 U nucleus is bombarded by neutrons (n) it undergoes a fission reaction, resulting in the formation of two new nuclei and
neutrons. The following equation is an example of one such fission process:
25 U+ n-Ba +36 Kr + 3n
Enter the isotope symbol for the barium (Ba) nucleus in this reaction.
Express your answer as an isotope.
▸ View Available Hint(s)
°= | ΑΣΦ
A chemical reaction does not occur for this question.
Submit
Part B
?
In another process in which 225U undergoes neutron bombardment, the following reaction occurs:
3U+ồn—£Sr+33 Xe+3ần
Enter the isotope symbol for the strontium (Sr) nucleus in this reaction.
Express your answer as an isotope.
►View Available Hint(s)
— | ΑΣΦ
Submit
?
A chemical reaction does not occur for this question.
Expert Solution

Step 1
In a nuclear reaction, the total mass number and total atomic number are conserved.
Hence while balancing a nuclear reaction we use the below two equations:
(i): Total mass number(A) on reactant side = Total mass number(A) on the product side
(ii): Total atomic number (Z) on the reactant side = Total atomic number(Z) on the product side.
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