In a metallurgical industry, acetylene gas used for welding is stored under compressed conditions with an initial pressure of 1.0 N/mm2 and a temperature of 240°C. The final pressure is twice the initial pressure and the exit temperature of the gas is 820°C. The heat capacity of the gas is given by: Cp = 6.7 + 0.0546 x 10-2 T + 0.032 x 10-5T2 where T is in K and Cp is in J/mol.K. Assume the gas to behave as an ideal gas. (0) Calculate the change in entropy of the gas (J/mol K). (ii) Calculate the change in entropy of the gas (J/mol K) when the final pressure is increased to 10 N/mm2. (iii) Based on change in entropy in part (i), comment on the nature of the process.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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In a metallurgical industry, acetylene gas used for welding is stored under compressed
conditions with an initial pressure of 1.0 N/mm2 and a temperature of 240°C. The final pressure
is twice the initial pressure and the exit temperature of the gas is 820°C. The heat capacity of
the gas is given by: Cp = 6.7 + 0.0546 x 10-2T + 0.032 x 10-5 T2 where T is in K and Cp is in
J/mol.K. Assume the gas to behave as an ideal gas.
(i)
Calculate the change in entropy of the gas (J/mol K).
(ii)
Calculate the change in entropy of the gas (J/mol K) when the final pressure is
increased to 10 N/mm2.
(ii)
Based on change in entropy in part (i), comment on the nature of the process.
Given data:
R= 8.314 J/mol.K
AS
In-
R T
1 cal = 4.184 J
°C + 273.15 =K
d(x") = n(x"-1)
1 N/mm2= 10 bar
xn+1
x" dx
n +1
Transcribed Image Text:In a metallurgical industry, acetylene gas used for welding is stored under compressed conditions with an initial pressure of 1.0 N/mm2 and a temperature of 240°C. The final pressure is twice the initial pressure and the exit temperature of the gas is 820°C. The heat capacity of the gas is given by: Cp = 6.7 + 0.0546 x 10-2T + 0.032 x 10-5 T2 where T is in K and Cp is in J/mol.K. Assume the gas to behave as an ideal gas. (i) Calculate the change in entropy of the gas (J/mol K). (ii) Calculate the change in entropy of the gas (J/mol K) when the final pressure is increased to 10 N/mm2. (ii) Based on change in entropy in part (i), comment on the nature of the process. Given data: R= 8.314 J/mol.K AS In- R T 1 cal = 4.184 J °C + 273.15 =K d(x") = n(x"-1) 1 N/mm2= 10 bar xn+1 x" dx n +1
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