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b) Calculate the temperature at the end of the compression process. T = c) Calculate the temperature at the end of the constant volume heat addition process. T3 = K

b) Calculate the temperature at the end of the compression process. T = c) Calculate the temperature at the end of the constant volume heat addition process. T3 = K

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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b) Calculate the temperature at the end of the compression process. T2 = K c) Calculate the temperature at the end of the constant volume heat addition process. T3 = d) Calculate the maximum cycle pressure. Pmaz = bar e) Calculate the maximum cycle temperature. Tmar = f) Calulate the temperature at point 5. T = K g) Calculate the pressure at point 5. P3 = bar h) Calculate the cycle efficiency as a percentage.
Transcribed Image Text:b) Calculate the temperature at the end of the compression process. T2 = K c) Calculate the temperature at the end of the constant volume heat addition process. T3 = d) Calculate the maximum cycle pressure. Pmaz = bar e) Calculate the maximum cycle temperature. Tmar = f) Calulate the temperature at point 5. T = K g) Calculate the pressure at point 5. P3 = bar h) Calculate the cycle efficiency as a percentage.
The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 4 = constant Нeat IN Adiabatic expansion Heat OUT (Constant volume heat rejection) Constant volume heat addition Adiabatic compression Volume (V) Using the Dual Air Standard Cycle and the following data: Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK;y = 1.4 Cycle compression ratio = 11 (v1/v2) Air conditions prior to compression: Pressure = 1.6 bar; Temperature = 298K Heat added at constant volume = 290000 J/kg Heat added at constant pressure = 579000 J/kg a) Calculate the pressure at the end of the compression process. P2 = bar Pressure (P) LO
Transcribed Image Text:The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 4 = constant Нeat IN Adiabatic expansion Heat OUT (Constant volume heat rejection) Constant volume heat addition Adiabatic compression Volume (V) Using the Dual Air Standard Cycle and the following data: Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK;y = 1.4 Cycle compression ratio = 11 (v1/v2) Air conditions prior to compression: Pressure = 1.6 bar; Temperature = 298K Heat added at constant volume = 290000 J/kg Heat added at constant pressure = 579000 J/kg a) Calculate the pressure at the end of the compression process. P2 = bar Pressure (P) LO
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