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The heat capacities of a gas is expressed by Cp = a + bT + cT^2. For nitrogen, a = 26.984; b = 5.91 x 10^ -3 ; and c = - 3.377 x 10^ -7 when Cp is in Joule/K - mole. How much heat is required to heat a mole of the system from 300K to 1000 K?

The heat capacities of a gas is expressed by Cp = a + bT + cT^2. For nitrogen, a = 26.984; b = 5.91 x 10^ -3 ; and c = - 3.377 x 10^ -7 when Cp is in Joule/K - mole. How much heat is required to heat a mole of the system from 300K to 1000 K?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The heat capacities of a gas is expressed by Cp = a + bT + cT^2. For nitrogen, a = 26.984; b = 5.91 x 10^ -3; and c = - 3.377 x 10^ -7 when Cp is in Joule/K - mole. How much heat is required to heat a mole of the system from 300K to 1000 K?
Transcribed Image Text:The heat capacities of a gas is expressed by Cp = a + bT + cT^2. For nitrogen, a = 26.984; b = 5.91 x 10^ -3; and c = - 3.377 x 10^ -7 when Cp is in Joule/K - mole. How much heat is required to heat a mole of the system from 300K to 1000 K?
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