In a lab experiment, 3.4g of methyl orange product was produced using the following: 2.25g sulfanilic acid, 1.3g sodium nitrite, 1.5ml N,N-dimethylaniline, 10ml NaOH and 2.5g NaCl. SHOW FULL WORKING AND ANSWER BOTH PARTS OF THE QUESTION:
In a lab experiment, 3.4g of methyl orange product was produced using the following: 2.25g sulfanilic acid, 1.3g sodium nitrite, 1.5ml N,N-dimethylaniline, 10ml NaOH and 2.5g NaCl. SHOW FULL WORKING AND ANSWER BOTH PARTS OF THE QUESTION:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In a lab experiment, 3.4g of methyl orange product was produced using the following: 2.25g sulfanilic acid, 1.3g sodium nitrite, 1.5ml N,N-dimethylaniline, 10ml NaOH and 2.5g NaCl.
SHOW FULL WORKING AND ANSWER BOTH PARTS OF THE QUESTION:
![3. How many moles of product did you make? Show your working.
The mass of product was
The molecular weight of product is
g/mol.
Therefore the number of moles of product was
_mol.
Calculate the reaction yield.
The stoichiometry between the limiting reagent and the product is
mol.
Therefore, the theoretical maximum number of moles of the product is
mol.
The actual number of moles of product was_
mol.
Therefore, the reaction yield was
_% (use 1 d.p.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74f2cd79-c5c5-445f-a150-039932640ac4%2F38206aa8-01dd-4b35-b3dc-243f8add6580%2Fsh6suar_processed.png&w=3840&q=75)
Transcribed Image Text:3. How many moles of product did you make? Show your working.
The mass of product was
The molecular weight of product is
g/mol.
Therefore the number of moles of product was
_mol.
Calculate the reaction yield.
The stoichiometry between the limiting reagent and the product is
mol.
Therefore, the theoretical maximum number of moles of the product is
mol.
The actual number of moles of product was_
mol.
Therefore, the reaction yield was
_% (use 1 d.p.)
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