In a completely randomized design, 12 experimental units were used for the first treatment, 14 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum of Variation of Squares Treatments Error Total 1,400 700 2,100 Degrees of Freedom 45 2 43 700 Mean Square O Ho: At least two of the population means are equal. H₂: At least two of the population means are different. O Ho: Not all the population means are equal. на: М1 = M2 = из At a 0.05 level of significance, is there a significant difference between the treatments? State the null and alternative hypotheses. о но H1 #M2 # Из На: М1 = М2 = из Ho: H₁ H₂ = μ3 H₂: Not all the population means are equal. F p-value

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Question
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Do not reject Ho. There is sufficient evidence to conclude that the means for the three treatments are not equal.
Do not reject Ho. There is not sufficient evidence to conclude that the means for the three treatments are not equal.
Reject Ho. There is not sufficient evidence to conclude that the means for the three treatments are not equal.
Reject Ho. There is sufficient evidence to conclude that the means for the three treatments are not equal.
Transcribed Image Text:Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Do not reject Ho. There is sufficient evidence to conclude that the means for the three treatments are not equal. Do not reject Ho. There is not sufficient evidence to conclude that the means for the three treatments are not equal. Reject Ho. There is not sufficient evidence to conclude that the means for the three treatments are not equal. Reject Ho. There is sufficient evidence to conclude that the means for the three treatments are not equal.
In a completely randomized design, 12 experimental units were used for the first treatment, 14 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance.
(Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
Source
Sum
of Variation of Squares
Treatments
Error
Total
1,400
700
2,100
Degrees
of Freedom
45
2
43
Но: M1 = M2 = M3
Hu₂ # U₂ # 1₂
700
Mean
Square
Ho:
: At least two of the population means are equal.
H₂: At least two of the population means are different.
Ho
Not all the population means are equal.
На: M1 = M2 = Из
At a 0.05 level of significance, is there a significant difference between the treatments?
State the null and alternative hypotheses.
O Ho: M₁ M₂ M3
#
#
На: M1 = M2 = M3
Но: M1 = M2 = Из
Ha: Not all the population means are equal.
F
st savod Tuesday October 11 2022 at 5.15 DM
p-value
Transcribed Image Text:In a completely randomized design, 12 experimental units were used for the first treatment, 14 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum of Variation of Squares Treatments Error Total 1,400 700 2,100 Degrees of Freedom 45 2 43 Но: M1 = M2 = M3 Hu₂ # U₂ # 1₂ 700 Mean Square Ho: : At least two of the population means are equal. H₂: At least two of the population means are different. Ho Not all the population means are equal. На: M1 = M2 = Из At a 0.05 level of significance, is there a significant difference between the treatments? State the null and alternative hypotheses. O Ho: M₁ M₂ M3 # # На: M1 = M2 = M3 Но: M1 = M2 = Из Ha: Not all the population means are equal. F st savod Tuesday October 11 2022 at 5.15 DM p-value
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