A researcher takes sample temperatures in Fahrenheit of 16 days from San Francisco (Group 1) and 22 daysfrom Atlanta (Group 2). Test the claim that the mean temperature in San Francisco is less than the meantemperature in Atlanta. Use a significance level of a = 0.10. Assume the populations are approximatelynormally distributed with unequal variances. You obtain the following two samples of data. Round answersto 4 decimal places.San Francisco77.494.87780.98473.484.99260.683.692.576.393.487.281.570.4Test Statistic =Atlanta85.492.880.287.980.677.9p-value =72.975.972.176.780.4What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbolsfor each of the 6 spaces.Ho: Select an answer ✓ ? V Select an answerH₁: Select an answer ✓ ? Select an answer VBased on the hypotheses, find the following:92.575.972.197.789.288.18092.28696.291.9The p-value is Select an answerThe correct decision is to Select an answerto alpha.the claim that the meanThe correct summary would be: Select an answertemperature in San Francisco is less than the mean temperature in Atlanta.

For the given data we need to test that the mean temperature in San Francisco is less than the mean…

Answered: A researcher takes sample temperatures…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher takes sample temperatures in Fahrenheit of 17 days from New York City and 18 days from Phoenix. Test the claim that the mean temperature in New York City is different from the mean temperature in Phoenix. Use a significance level of α=0.05. Assume the populations are approximately normally distributed with unequal variances. You obtain the following two samples of data. New York City Phoenix 99 94.2 95.5 72 93.2 86.8 102 122.1 85.4 114.4 80 94.7 86.4 89.7 75.4 104.7 79.5 77.6 83.4 106.8 64.3 98.6 65.5 91.5 87.7 82 104 97.7 74.3 64.9 59.5 82 82.8 72 116.2 The Hypotheses for this problem are: H0: μ1 = μ2 H1: μ1μ2 Find the p-value. Round answer to 4 decimal places. Make sure you put the 0 in front of the decimal. p-value =
Please solve part c, d and e only. DO NOT SOLVE PART a AND b. I need answers for part c, part d and part e.
A developmental psychologist is interested in studying how long babies gaze at a photograph of a human face. To test this question, she shows a picture to a sample of six babies and records the length of their gaze in seconds. The data are as follows: 12, 17, 18, 20, 20, 29. Calculate the mean, median, mode, range, variance and standard deviation for the sample.
Periodically, customers of a financial services company are asked to evaluate the company's financial consultants and services. Higher ratings on the client satisfaction survey indicate better service, with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use ? = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating. Assume the population variances are unequal. Consultant A Consultant B n1 = 16 n2 = 10 x1 = 6.85 x2 = 6.25 s1 = 0.69 s2 = 0.75 (a) State the null and alternative hypotheses. -H0:?1 − ?2 = 0 Ha:?1 − ?2 = 0 -H0:?1 − ?2 > 0 Ha:?1 − ?2 = 0 -H0:?1 − ?2 ≠ 0 Ha:?1 − ?2 = 0 -H0:?1 − ?2 = 0 Ha:?1 − ?2 > 0 -H0:?1 − ?2 = 0 Ha:?1 − ?2 ≠ 0 (b) Compute the value of the test statistic. (Round your answer to three decimal places.)…
Pls do fast its urgent and i will rate instantly for sure Solution must be in typed form
Consider the following data: −10, −10, 0, 3, −10, 3, 3 Step 1 of 3: Calculate the value of the sample Variance. Round your answer to one decimal place. Step 2 of 3: Calculate the value of the sample deviation. Round your answer to one decimal place. Step 3 of 3: Calculate the value of the range.
Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year x1 = 75.8 | x,= 76.2 si= 47.61 s3= = 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…
Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…
A researcher takes sample temperatures in Fahrenheit of 20 days from Minneapolis and 18 days from Cleveland. Use the sample data shown in the table. Test the claim that the mean temperature in Minneapolis is different than the mean temperature in Cleveland. Use a significance level of α=0.01. Assume the populations are approximately normally distributed with unequal variances.Note that list 1 is longer than list 2, so these are 2 independent samples, not matched pairs. Minneapolis Cleveland 70.1 66.1 69.5 65.9 65.7 61 71.7 62.8 62 67.9 75.3 74.5 63.2 69.1 62 72.5 76.9 80.4 71.3 72.7 70.9 70.4 70.5 76.6 65.1 62.2 76.2 66.1 70.3 86 69.5 81 80.2 68.3 74.3 63.3 70.7 64.6 The Null Hypotheses is: H0: μ1 - μ2 = 0 What is the alterative hypothesis? Select the correct symbols for each space. (Note this may view better in full screen mode.)HA: μ1 - μ2 Based on these hypotheses, find the following. Round answers to 4 decimal…
Two companies produce widgets of varying quality. An important measure of quality is the number of days the widgets can go before they need to be replaced. Do the following data provide evidence that the quality of widgets from the two companies differ? Round the p-value to three decimal places. Do not assume equal variances. Widget Life in Days from Company 1 Widget Life in Days from Company 2 12.0 52.2 14.0 45.8 48.4 44.6 47.0 57.5 50.4 44.2 57.4 50.8 30.8 43.0 30.0
Please do 3 and 4.
The coefficient of variation (CV) measures the dispersion of the data relative to the sample mean. Suppose the sample mean of a particular variable is 550 and the sample variance is 6400. What is the CV? O 32.6% O 1.163.6% O 10.7% O 14.5%

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