**Cathode Ray Tube (CRT) Explanation**The illustration depicts the functioning of a Cathode Ray Tube (CRT), which is a fundamental component of older television sets and oscilloscopes. In this setup:1. **Electron Gun**: Electrons are generated from a heated filament acting as the source. These electrons are then accelerated towards an anode.2. **Motion of Electrons**: After passing through the anode, the electrons travel in the z-direction at a velocity of \(9.10 \times 10^6\) m/s.3. **Deflection Mechanism**: - **Vertical Deflection Plates (A)**: Electrons pass between a pair of vertical parallel plates. This arrangement allows for deflection in the horizontal direction. - **Horizontal Deflection Plates (B)**: Electrons also traverse between horizontal parallel plates. This set enables deflection in the vertical direction.4. **Dimensions of Plates**: Each of the four plates described is a square measuring 2.30 cm per side. The separation between plates of each pair is 1.50 cm.5. **Diagram Details**: - **Side View**: Shows the electron beam path from the cathode to the anode, affected by a uniform electric field (represented by arrows indicating direction). - **Conductive Coating**: Covers the internal surface of the CRT to help focus and direct the electrons. - **Fluorescent Screen**: At the end of the tube, where the electron beam strikes to create visible images or signals.Overall, the CRT operates by manipulating the path of electron beams to create displays through controlled deflection and subsequent illumination of a fluorescent screen. ### Transcription for Educational Website#### Diagram ExplanationThe diagram shows an electron beam moving horizontally across a setup consisting of two sets of plates. In the side view of the setup:- **Electron beam**: Represented by a yellow arrow moving from left to right, indicating the trajectory of the electrons.- **Plates (A)**: The region where the electric field is zero, shown in green.- **Plates (B)**: An area with a uniform electric field, depicted in red. The electric field deflects the electron beam downward as indicated by the green arrows pointing downwards.- **Anode**: Labels the positive side at the end of the plates.- **Fluorescent screen**: Positioned at the far right, where the deflected electron beam lands.#### Educational ContentThe electric field between plates (A) is zero. As the beam exits the space between plates (B), it has been deflected 1.90 mm downward (\(\Delta y = -1.90 \text{ mm}\)). **Question**: What is the magnitude of the electric field between plates (B)? **Given**: - Deflection \(\Delta y = -1.90 \text{ mm}\)- Mass of electron = \(9.109 \times 10^{-31} \text{ kg}\)Calculate the electric field magnitude in \(\boxed{\phantom{N/C}} \text{N/C}\).

u = 9.10 ×106 m/s z=150 cm = 0.015 m ∆y=1.90 mm = 0.0019 m

In a cathode ray tube (CRT), after the electrons pass through the anode, they are moving in the z-direction at a speed of 9.10 × 10º They then pass between a pair of vertical parallel plates (A) and then between a pair of horizontal parallel plates (B). All four of these plates are squares 2.30 cm on a side. The plates of each pair are separated by 1.50 cm. m/s.

In a cathode ray tube (CRT), after the electrons pass through the anode, they are moving in the z-direction at a speed of 9.10 × 10º They then pass between a pair of vertical parallel plates (A) and then between a pair of horizontal parallel plates (B). All four of these plates are squares 2.30 cm on a side. The plates of each pair are separated by 1.50 cm. m/s.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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