In 1999, the average percentage of women who received prenatal care per country was 80.1%. The table below contains the percentage of woman receiving prenatal care in 2009 for a random sample of countries. Do the data show that the average percentage of women receiving prenatal care in 2009 was higher than in 1999? Test at the 1% level. percentage of women receiving prenatal care in percent 95 81.9

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Hello plz help with the following I left blank because I didnt understand it.

Part P/S Blanks that don't show:

-A randomly selected country.

-The mean percentage of women receiving prenatal care in 34 randomly selected countries.

-All countries

-The mean percentage of women receiving prenatal care of all countries.

-The percentage of women receiving prenatal care of a randomly selected country.

-34 randomly selected countries

In 1999, the average percentage of women who received prenatal care per country was 80.1%. The table
below contains the percentage of woman receiving prenatal care in 2009 for a random sample of countries.
Do the data show that the average percentage of women receiving prenatal care in 2009 was higher than in
1999? Test at the 1% level.
P: Parameter
percentage of women receiving prenatal care in percent
95
81.9
80.6
H₂ μV V 80.1
P
S
HA: VE
100
94.51
93.63
97.9
100
94.51
96.24
88.4
93.63
92.2
What is the correct parameter symbol for this problem?
PV
What is the wording of the parameter in the context of this problem?
Select an answer
80.1
no outliers in the data
outliers in the data
80.6
91.5
88.4
H: Hypotheses
Fill in the correct null and alternative hypotheses:
100
92.47
100
92.41
80.6
94.51
On(1-P) ≥ 10
Onp > 10
ON> 201
On> 30 or normal population
On(1-p) 10
Do is unknown
□n(p) ≥ 10
is known
81.9
97.9
95.8
93.4
95
95.8
94.3
80.34
93
97.95
88.4
93.63
percent
A: Assumptions
Since Select an answer V information was collected from each object, what conditions do we need
to check?
Check all that apply.
percent
Transcribed Image Text:In 1999, the average percentage of women who received prenatal care per country was 80.1%. The table below contains the percentage of woman receiving prenatal care in 2009 for a random sample of countries. Do the data show that the average percentage of women receiving prenatal care in 2009 was higher than in 1999? Test at the 1% level. P: Parameter percentage of women receiving prenatal care in percent 95 81.9 80.6 H₂ μV V 80.1 P S HA: VE 100 94.51 93.63 97.9 100 94.51 96.24 88.4 93.63 92.2 What is the correct parameter symbol for this problem? PV What is the wording of the parameter in the context of this problem? Select an answer 80.1 no outliers in the data outliers in the data 80.6 91.5 88.4 H: Hypotheses Fill in the correct null and alternative hypotheses: 100 92.47 100 92.41 80.6 94.51 On(1-P) ≥ 10 Onp > 10 ON> 201 On> 30 or normal population On(1-p) 10 Do is unknown □n(p) ≥ 10 is known 81.9 97.9 95.8 93.4 95 95.8 94.3 80.34 93 97.95 88.4 93.63 percent A: Assumptions Since Select an answer V information was collected from each object, what conditions do we need to check? Check all that apply. percent
Check those assumptions:
1. Is the value of a known? nov
o
2. Which of the following is the correct modified boxplot?
80.34
80.34
80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
percentage of women receiving prenatal care in percent
Q
O
80.34
80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
percentage of women receiving prenatal care in percent
Q
O
84.37
3. n
+
nº on
80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
percentage of women receiving prenatal care in percent
Q
O
t=
88.4
?V-
88.4
X-H
To
t-
9363 95.8
884
80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
percentage of women receiving prenatal care in percent
O
Q
91.015
93.63 95.8
which is ? V
Is it reasonable to assume the population is normally distributed?
Select an answer
N: Name the test
The conditions are met to use a [Select an answer
P-value-
Are there any outliers? No, the modified boxplot shows no outliers
M: Make a decision
9363
T: Test Statistic
The symbol and value of the random variable on this problem are as follows:
95.8
percent
The test statistic formula set up with numbers is as follows:
Round values to 3 decimal places.
S: State a conclustion
There is
Select an answer
is more than
Since the p-value ? V
97.9
H
The final answer for the test statistic from technology is as follows:
Round to 2 decimal places.
O: Obtain the P-value
Report the final answer to 4 decimal places.
It is possible when rounded that a p-value is 0.0000
percent
, we Select an answer V
V significant evidence to conclude
Transcribed Image Text:Check those assumptions: 1. Is the value of a known? nov o 2. Which of the following is the correct modified boxplot? 80.34 80.34 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 percentage of women receiving prenatal care in percent Q O 80.34 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 percentage of women receiving prenatal care in percent Q O 84.37 3. n + nº on 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 percentage of women receiving prenatal care in percent Q O t= 88.4 ?V- 88.4 X-H To t- 9363 95.8 884 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 percentage of women receiving prenatal care in percent O Q 91.015 93.63 95.8 which is ? V Is it reasonable to assume the population is normally distributed? Select an answer N: Name the test The conditions are met to use a [Select an answer P-value- Are there any outliers? No, the modified boxplot shows no outliers M: Make a decision 9363 T: Test Statistic The symbol and value of the random variable on this problem are as follows: 95.8 percent The test statistic formula set up with numbers is as follows: Round values to 3 decimal places. S: State a conclustion There is Select an answer is more than Since the p-value ? V 97.9 H The final answer for the test statistic from technology is as follows: Round to 2 decimal places. O: Obtain the P-value Report the final answer to 4 decimal places. It is possible when rounded that a p-value is 0.0000 percent , we Select an answer V V significant evidence to conclude
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