In 1, why if we separate the CD column, all the R1 force is in the column? But in 2, if we separate the CD column, half of the force F is in the column .
In 1, why if we separate the CD column, all the R1 force is in the column? But in 2, if we separate the CD column, half of the force F is in the column ...
#structure_analysis
The given frame is statically indeterminate.
In this case, the total force will be carried by column CD, because the stiffness(K) of column CD is much more than the stiffness of column BA. In other words, the stiffness of column BA is Zero while the stiffness of column CD is 1.
The Horizontal force 'F' will be distributed in the two columns concerning their distribution factors(D).
Distribution factor for column CD is given by:-
Hence, the distribution factor of column CD is 1.This means that column CD will take 100% of the applied horizontal force 'F'.
Similarly, for column BA, the distribution factor is:-
Since the distribution factor for column BA is zero. It will not take any fraction of the applied horizontal force'F'.
The given frame is statically indeterminate.
Similarly, in this case, both columns BA and CD, have equal stiffness, because the end conditions of both the columns are the same. (At one end it is fixed and at the other end there is a guided roller).
Hence,
Hence their distribution factors are 50% each. This means both columns will share the horizontally applied force 'F' by 50% each.
Hence force in each column is F/2.
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