Improve the given code below, make sure that the code will require input from the user.  Problem: Write a JavaScript function that would accept a string and checks whether a passed string is palindrome?   function check_Palindrome(str_entry){ var cstr = str_entry.toLowerCase().replace(/[^a-zA-Z0-9]+/g,''); //changes the str -> lowercase && rem all non-alpha numeric chars var count = 0; if(cstr === ""){ console.log("String is not found"); return false; } if((cstr.length) % 2 === 0){ //checks if the str is even or odd count = (cstr.length) / 2; } else { console.log("Num4"); if(cstr.length === 1){ //if str length === 1 then it is palindrome console.log("The string is a palindrome."); return true; } else { count = (cstr.length - 1) / 2; //if the str length is odd, ignores the mid char } } var p; for(p = 0; p < count; p++){ if(cstr[p] != cstr.slice(-1-p)[0]){ //compares char that doesn't match console.log("The string is not a palindrome."); console.log("\n"); return false; } } console.log("The string is a palindrome."); return true; } check_Palindrome('010'); check_Palindrome('1011

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Improve the given code below, make sure that the code will require input from the user. 
Problem: Write a JavaScript function that would accept a string and checks whether a passed string is palindrome?

 

function check_Palindrome(str_entry){
var cstr = str_entry.toLowerCase().replace(/[^a-zA-Z0-9]+/g,''); //changes the str -> lowercase && rem all non-alpha numeric chars
var count = 0;

if(cstr === ""){
console.log("String is not found");
return false;
}
if((cstr.length) % 2 === 0){ //checks if the str is even or odd
count = (cstr.length) / 2;
} else {
console.log("Num4");
if(cstr.length === 1){ //if str length === 1 then it is palindrome
console.log("The string is a palindrome.");
return true;
} else {
count = (cstr.length - 1) / 2; //if the str length is odd, ignores the mid char
}
}
var p;
for(p = 0; p < count; p++){
if(cstr[p] != cstr.slice(-1-p)[0]){ //compares char that doesn't match
console.log("The string is not a palindrome.");
console.log("\n");
return false;
}
}
console.log("The string is a palindrome.");
return true;
}
check_Palindrome('010');
check_Palindrome('1011');

 

 

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