I need help solving this in JAVA 1 import java.util.Scanner;2.3 public class Compare {4public static void main(String args) {final int SIZE_LIST = 4;int] keysList = new int[SIZE LIST];int[] itemsList = new int[SIZE_LIST];int i;Scanner input6.8.9.10= new Scanner(System.in);1112keysList[0]keysList[1]keysList[2] = input.nextInt();keysList[3] = input.nextInt();input.nextInt();input.nextInt();13141516itemsList[0] = input.nextInt(); IitemsList[1] = input.nextInt();itemsList[2] = input.nextInt();itemsList[3] = input.nextInt();17181920!!2122/* Your code goes here */2324System.out.println();}252627 } For any element in keysList with a value smaller than 40, print the corresponding value in itemsList, followed by a semicolon (nospaces).Ex: If the input is:32 105 101 35-10 20 30 40the output is:10;40;

import java.util.Scanner; 3 public class Compare { public static void main(String args) { final int SIZE_LIST = 4; int keysList new int[SIZE_LIST]; int[ itemsList new int[SIZE_LIST]; int i; Scanner input = new Scanner(System.in); !! 8. %3D 10 %3D 11 12 keysList[0] = input.nextInt(); keysList[1] = input.nextInt(); %3! 13 %3!

import java.util.Scanner; 3 public class Compare { public static void main(String args) { final int SIZE_LIST = 4; int keysList new int[SIZE_LIST]; int[ itemsList new int[SIZE_LIST]; int i; Scanner input = new Scanner(System.in); !! 8. %3D 10 %3D 11 12 keysList[0] = input.nextInt(); keysList[1] = input.nextInt(); %3! 13 %3!

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Array

The simplest way to start thinking about an array is as a collection, or a set of elements. In programming, these elements may be constants, variables, functions and pointers.

Question

I need help solving this in JAVA

1 import java.util.Scanner;
2.
3 public class Compare {
4
public static void main(String args) {
final int SIZE_LIST = 4;
int] keysList = new int[SIZE LIST];
int[] itemsList = new int[SIZE_LIST];
int i;
Scanner input
6.
8.
9.
10
= new Scanner(System.in);
11
12
keysList[0]
keysList[1]
keysList[2] = input.nextInt();
keysList[3] = input.nextInt();
input.nextInt();
input.nextInt();
13
14
15
16
itemsList[0] = input.nextInt(); I
itemsList[1] = input.nextInt();
itemsList[2] = input.nextInt();
itemsList[3] = input.nextInt();
17
18
19
20
!!
21
22
/* Your code goes here */
23
24
System.out.println();
}
25
26
27 }

For any element in keysList with a value smaller than 40, print the corresponding value in itemsList, followed by a semicolon (no
spaces).
Ex: If the input is:
32 105 101 35
-10 20 30 40
the output is:
10;40;

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