Imagine you have been given a liquid culture of yeast with a starting concentration of 3.67 x 10' cells/ml and are asked to carry out the sample dilution process shown in the figure below. 100μl 100μl 100μl 100μl 100μl 0.9ml 0.9ml 0.9ml H2O H₂O 6.9ml 0.9ml H₂O H₂O H₂O Original 10-1 102 10-3 104 Culture 105 100μl 100μl 100μl Plate A Plate B Plate C a. How many colonies should have been present on Plate A in this example? - Answers must be whole numbers as partial colonies are not expected. b. Imagine you carried out the same dilution scheme shown in the figure above, but now, you do not know the concentration of the original culture. If you counted 163 colonies on Plate B, what is the concentration of cells/ml in the original culture?
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- A culture of S. cerevisea has an overnight OD of 2.3 (1.0 OD is approx 1.0x107 cells/ml) You will be plating 100µl onto agar and want the final count of colonies on the plate to be around 300 colonies. How much of the 2.3 OD culture must you use to get a 500µl subdilution (with sterile water), so that you have diluted enough to get approx 300 colonies per 100ulTime point (min) Absorbance of culture at 660nm Approximate cell concentration Approximate # cells in 1mL extract 0 0.298 1.49 x 108 cells/mL 1.49 x 108 cells 10 0.316 1.58 x 108 cells/mL 1.58 x 108 cells 20 0.374 1.87 x 108 cells/mL 1.87 x 108 cells 30 0.429 2.145 x 108 cells/mL 2.145 x 108 cells 40 0.512 2.56 x 108 cells/mL 2.56 x 108 cells 50 0.544 2.72 x 108 cells/mL 2.72 x 108 cells 60 0.607 3.035 x 108 cells/mL 3.035 x 108 cells a. Using these data, prepare a growth curve of this strain ofEscherichia coli (E. coli).b. Estimate the doubling time for this strain of E. Coli. Clearly showhow you estimated this value from the empirical data presented.Nutrient Agar (NA) is a general purpose medium used for the cultivation of a wide variety of non- fastidious microorganisms (Merck, 2000). Its ingredients are listed in Table 2. You are tasked to prepare 300ml of NA, determine the amount of ingredients and write in column 3 in Table 2. Show your calculations. *A sample calculation was made for you. Peptone = 300 ml x 0.5% = 1.5 g Table 2. Medium Composition of Nutrient Agar (NA) with the recommended proportions (Merck, 2019) Ingredients In % In Grams/300ml Peptone 0.5 *1.5 Meat extract 0.3 Agar 1.5 Distilled Water As needed
- Now prepare a 500 ml media having ¼ strength MS with 5mM BAP, 5.5 mg/l Kn and coconut water 10%. Stocks are MS Macro 10X, micro 20X, FeEDTA 10X, Organic 100X, BAP and Kn 5gm/100ml. If you need anything else then you add accordingly. BAP has a MW of 225.3. Sucrose and Myo-inositol is not mentioned in the question. These you need to add. Consistency of the medium is also mentioned.Calculate the estimated concentration of test agent that inhibit cell growth by 50% ( GI50) valueWhen the yeast cells have completely re-hydrated, measure out 1.8 mL of well-mixed yeast suspension (0.2% yeast) into each of two new 15 mL centrifuge tubes. Add 200 μL of a 10% (w/v) Sodium Azide*** in YGM solution to one of the 15 mL tubes with yeast suspension. Add 200 μl of YGM to the other 15 mL tube of yeast suspension for your Control. Let both tubes incubate at room temperature for 30 min, vortexing every ~5 minutes What is the % concentration of azide in this sample during metabolic inhibition?What is the % concentration of yeast in this sample during metabolic inhibition?
- If 0.1 ml of a 1 * 10−6 dilution plate contains 56 colonies, calculate thenumber of cells per ml of the original cultureExplain how to prepare 250 ml liquid and 500 ml solid form separately from LB (Luria Bertani) medium whose components and concentrations are given below. Yeast extract 5 g/L Peptone 10 g/L NaCl 10 g/L Agar 1.5 g/LA bacterial culture has a concentration of 3.2 x 108 cells /mL. You dilute this culture as follows: 1/50, then 10-3 and finally 1/20. If you then plate 0.2 mL of the final dilution, how many CFU would you expect following incubation?
- The number of cells in a culture is estimated based on turbidity. If the following standards are used for comparison: Number of cells/mL Optical Density (measure of turbidity) 0.025 0.050 000'000'৮ 000 000'000' కరరక How many cells are present in a culture that has an optical density of 0.075? O A. Less than 1,000,000 O B. Between 2,000,000 and 4,000,000 O C. 16,000,000 O D. Between 4,000,000 and 8,000,000 Reset SelectionThe number of bacterial cells in a culture broth is to be determined by a culture technique. Serial dilutions were performed and a 1 mL aliquot from each dilution was mixed with warm molten agar and poured into a Petri dish. The numbers of bacterial colony forming units (CFU) after overnight incubation are shown in the table below. What is the number of colony forming units per mL of the culture broth? Choose only the most appropriate plate for your calculation. Give your answer as the number only (do not add text for the units). You may use scientific notation with the format 1.12e+6 (that is, 1.12 x 106 cfu/mL). (Note: Canvas will then display your answer a whole number.) Plate Dilution -3 Plate 1 10 dilution Plate 2 10-4 dilution Plate 3 10-5 dilution Plate 4 10 dilution Plate 5 10 dilution -8 Plate 6 100 dilution *Too many to count Number of colony forming units (CFU) TMTC* 1,957 65 21 1 0 mThe number of bacterial cells in a culture broth is to be determined by a culture technique. Serial dilutions were performed and a 1 mL aliquot from each dilution was mixed with warm molten agar and poured into a Petri dish. The numbers of bacterial colony forming units (CFU) after overnight incubation are shown in the table below. What is the number of colony forming units per mL of the culture broth? Choose only the most appropriate plate for your calculation. Give your answer as the number only (do not add text for the units). You may use scientific notation with the format 1.12e+6 (that is, 1.12 x 106 cfu/mL). (Note: Canvas will then display your answer a whole number.) Plate Dilution Plate 1 10 dilution Plate 2 10 dilution -5 Plate 3 10 dilution Plate 4 10 dilution Plate 5 107 dilution -8 Plate 6 100 dilution *Too many to count Number of colony forming units (CFU) TMTC* TMTC* TMTC* 867 154 18