Illustration 55. Fit a Poisson distribution to the following frequency distribution and estimate the total cost of corrections. No. of misprints on a page : No. of pages: Cost of Correction Per page (Rs.) 2 3 4 62 2.50 113 20 1.50 3 1 3.50 514
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- Assuming that workers' salaries in your company are uniformly distributed between $10,000 and $50,000 per year. Find the amount of money that 35% of the workers make more than that value?Consider the following partially filled frequency table: Value Frequency 0.5 1.0 2.9 Calculate the mean (to 2 d.p.). Cumulative Relative Frequency Frequency 0.2 39 1001. Find the percentage of N.d. observations with a zz-score between z1= -3.04 and z2 = 2.85. Give your answer to two decimal places. 2. Find the proportion of N.d. observations with a zz-score between z1= -2.95 and z2 = 0.70. Give your answer to four decimal places.
- Suppose that we want to determine if the average amount of timespent online by the students is lessthan 4.5 hours/day. To this end, weconduct a survey of students and askthem how long they spend online perday. We obtain the following results:4.1, 4.3, 4.3, 4.5, 4.6, 4.3, 4.1, 4.6,4.7, 4.6, 4.7, 4.1, 4.3, 4.3, 4.5, 4.6,4.3, 4.1, 4.6, 4.7, 4.6, 4.7, 4.5, 4.6,4.3, 4.1 Assume that the number ofhours spent online has a normal distribution. Test your hypotQ2. A laundry for car wash found that the average, for small size car, cleaning time is 5 mins in the morning and 6.5 mins at evening time when a sample of size 30 is taken at the two time periods. From the previous record, the laundry manager knew that car oj = 2 mins for the morning shift and oz = 2.5 mins for morning and evening repectively. Find the interval estimate for 4 - 42 with 90% confidence level.Suppose that 50 measurements were taken and the mean was calculated to be 4.55. Assume next that one of the data items was 19.4This was assumed to be an outlier as was discarded. What would be the mean of the remaining 49 numbers? I
- A political newspaper, Politically Sound, is interested in the distances voters in Rising Falls County live from their nearest polling station. Politically Sound has hired you to estimate the population mean of all such distances for voters in this county. To estimate this population mean, you select a random sample of 17 Rising Falls County voters and record the distance (in km) each voter lives from their nearest polling station. Assume the population is approximately normally distributed. Based on your sample, follow the steps below to construct a 99% confidence interval for the population mean of all the distances voters in Rising Falls County live from their nearest polling station. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Number of voters 17 Sample mean 4.757 Sample standard deviation 2.363 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the…a) The average temperature (Centigrade) in London varies from 14C to 31C during the year. i. Calculate indices based on March, base = 100 ii. What is the %age variation between the highest and the lowest temperatures? Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Temp C 15 22 19 24 29 28 31 28 27 22 18 14 Index b) Below are the no of customers, visiting a local Tesco Express, in the first week of holiday season. The store manager would like to avoid stock out in the busy period. Provide forecast of sales on Saturday next week, using 3 point moving average and seasonal variation. Assume same seasonal variation next period.Average monthly wages (per employee) in 4 sectors of an economy are as follows: industry: 2000 dinars, building: 2200 dinars, agriculture: 1500 dinars, services: 1800 dinars. Number of people employed in the four sectors are 5 million, 2 million, 6 million, and 2 million, respectively. Using the concept of harmonic mean compute the average monthly wages in the economy under consideration.
- For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.In a marketing survey, a random sample of 992 supermarket shoppers revealed that 274 always stock up on an item when they find that item at a real bargain price. (a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.) (b) Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.)lower limit upper limit Give a brief explanation of the meaning of the interval. We are 95% confident that the true proportion of shoppers who stock up on bargains falls within this interval.We are 5% confident that the true proportion of shoppers who stock up on bargains falls above this interval. We are 5% confident that the true proportion of shoppers who…Suppose the lengths of human pregnancies are normally distributed with µ = 266 days and o= 16 days. Complete parts (a) and (b) below. (Type integers or decimals.) A. The proportion of human pregnancies that last less than B. The proportion of human pregnancies that last more than days is days is Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts less than B. The probability that a randomly selected human pregnancy lasts more than (b) The figure to the right represents the normal curve with µ = 266 days and o = 16 days. The area between x = 280 and x = 295 is 0.1558. Provide two interpretations of this area. days is days is Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or…your car is more crowded than you think. table 5.8 reports results from a 1969 personal transportation survey on "home-to-work" trips in metropolitan areas. The survey stated that the average car occupancy was 1.4 people. check that calculation.
