I,j,k are unit vectors in the positive x,y,a direction. What is the electric field at (0,0,h) due to the ring of radius R with the center at (0,0,0) carrying a total charge Q uniformly distributed along its circumference according to Coulomb's Law?
I,j,k are unit vectors in the positive x,y,a direction. What is the electric field at (0,0,h) due to the ring of radius R with the center at (0,0,0) carrying a total charge Q uniformly distributed along its circumference according to Coulomb's Law?
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Question
I,j,k are unit vectors in the positive x,y,a direction. What is the electric field at (0,0,h) due to the ring of radius R with the center at (0,0,0) carrying a total charge Q uniformly distributed along its circumference according to Coulomb's Law? What formula would I use to solve this problem?
Expert Solution
Step 1
Introduction:
The charge on the ring is uniformly distributed so the charge density of the ring will be
The ring is centered at the origin in the x,y plane so, the axis of the ring will be represented by the z-axis.
The distance vector given is,
The electric field at due to the small element of the ring can be calculated using the Coulomb law and then can be integrated for the whole of the ring.
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