II Review | Constants | Periodic The 2.6-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.40 T Part A What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express your answer in webers. Wb Submit Request Answer Part B What is the magnetic flux through the loop when it is tilted at a 60° angle? Express your answer in webers. ) ? Wb Figure < 1 of 1> Submit Request Answer Provide Feedback (a) (b) Solenoid

II Review | Constants | Periodic The 2.6-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.40 T Part A What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express your answer in webers. Wb Submit Request Answer Part B What is the magnetic flux through the loop when it is tilted at a 60° angle? Express your answer in webers. ) ? Wb Figure < 1 of 1> Submit Request Answer Provide Feedback (a) (b) Solenoid

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

2a I' A current I is carried in the direction shown in the figure in the conducting wires of a right triangular loop with perpendicular side length a. If this loop is placed at a distance 2a away from a very long straight wire carrying a current I' which is parallel to the longer side of the loop, what is the total magnetic force on the loop? a) b) Iin (1+-A 디름-Im(2+ )) d) 쁘[2v2-In(-2)) [In (1 +)- Holl' Holl' c) spoll" 3/2 +In (1+)i
Review | Constants A rectangular loop of wire with dimensions 1.80 cm by 7.00 cm and resistance 0.800 is being pulled to the right out of a region of uniform magnetic field. The magnetic field has magnitude 2.40 T and is directed into the plane of (Figure 1). Part A At the instant when the speed of the loop is 3.00 m/s and it is still partially in the field region, what is the magnitude of the force that the magnetic field exerts on the loop? Express your answer with the appropriate units. Figure 1 of 1 X με FB = Value Units Submit Request Answer Part B wwww ? What is the direction of the force that the magnetic field exerts on the loop? to the right downward upward to the left Submit Request Answer Provide Feedback Next >
QUESTION 3 An 80-cm-long conducting rod moves to the right with a constant velocity along frictionless metal rails "ab" and "dc" as shown in the diagram below. At the same time, a uniform magnetic field of strength 1.8 T points out of the page and perpendicular to the plane of the rod-and-frame device (the positive z- direction). The resistance in the closed loop is 7.00 N. If the current across the resistor is 2.0 A, what is the speed of the conducting rod along the rails? Fig 5: A slide-wire generator X L = 80 cm z (out of page) - Дх — b a B (out of page) B (out of page) Conducting R Rails 000 ΔΑ O O O d Conducting Loop Conducting Rod O a. 6.4 m/s O b.7.9 m/s O c. 14 m/s O d. 9.7 m/s O e. 11 m/s
3
1
to the left O to the right Additional Materials B Reading -/10 Points] DETAILS OSCOLPHYS2016 22.8.WA.040. NOTES ASK YOUR TEACHER PRACTICE ANOTHER Calculate the magnetic field strength needed on a 180-turn square loop 20.0 cm on a side to create a maximum torque 280 N m, if the loop is carrying 25 A. T Additional Materials Reading --/10 Points] DETAILS OSCOLPHYS2016 22.10.P.055.
Fast pls solve this question correctly in 5 min pls I will give u like for sure A long cable of circular cross section and diameter 2 cm has a long cylindrical hole of diameter 1 mm drilled in it parallel to the cable axis. The distance be- tween the axis of the hole and the cable axis is 5 mm. If the cable has a uniform steady current density of 10^5 A · m−2 flowing through it, calculate the magnetic field at the centre of the cable. (Hint: use the principle of superposition.)