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A certain single loop of wire has a resistance of 0.25 N and is positioned in an applied magnetic field that points out of the plane, as shown below. The magnetic field strength is given by B = -t² + 3t, where B is in tesla and t is in seconds. At t = 0.4 s, the induced current is 0.050 A. Calculate the area of the loop. direction of field

A certain single loop of wire has a resistance of 0.25 N and is positioned in an applied magnetic field that points out of the plane, as shown below. The magnetic field strength is given by B = -t² + 3t, where B is in tesla and t is in seconds. At t = 0.4 s, the induced current is 0.050 A. Calculate the area of the loop. direction of field

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can i get simple solution please 

thank you 

A certain single loop of wire has a resistance of 0.25 N and is positioned in an applied magnetic field that points out of the plane, as shown below. The magnetic field strength is given by B = -t + 3t, where B is in tesla and t is in seconds. At t= 0.4 s, the induced current is 0.050 A. Calculate the area of the loop. direction of field
Transcribed Image Text:A certain single loop of wire has a resistance of 0.25 N and is positioned in an applied magnetic field that points out of the plane, as shown below. The magnetic field strength is given by B = -t + 3t, where B is in tesla and t is in seconds. At t= 0.4 s, the induced current is 0.050 A. Calculate the area of the loop. direction of field
Expert Solution
Step 1

given  that : R= 0.25Ω 

B= -t2+ 3t 

i= .050A

we have to calculate the area for t=.4s

since we have formula from Lentz law 

ε=-dϕdt

Φ=∫B.da

 Also, ε= iR

putting the given values in the formula

we get 

i=-1Rdϕdt

∴i=-1Rd∫B.dadt 

 

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