(ii) A student was given 400 cm of aqueous ammonia solution, NH, (aq). The student was asked to determine how many moles of NH., had been dissolved to prepare the solution. The student titrated 25.0cm of NH, (aq) and found that it reacted exactly with 32.5cm3 of 0.100 mol dm sulturic acid. The equation for this reaction is shown below. 2NH(aq) + H,SO,(aq) → (NH,SO,(aq) Calculate the amount, in moles, of NH, in the original 400 cm solution.

Q: In a titration experiment, a chemist finds that a 25.0 mL solution of aq. HCl requires 51.3 mL of…

A: n-factor of HCl, nHCl = 1 Molarity of HCl, MHCl = ? Volume of HCl, VHCl = 25 mL = 0.025 L n-factor…

Q: By titration, it is found that 62.5 mL of 0.176 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Step 1:To find the concentration of the HCl solution, we can use the equation for neutralization…

Q: 2. The arsenic in a 1.203-g sample of a pesticide was converted to H3ASO4 by suitable treatment. The…

A: Given that,Weight of pesticide = 1.203gVolume of  = 40 mLMolarity of = 0.05871 MVolume of  = 9.63…

Q: 31.  10.0 mL. of concentrated of H3PO4(aq) is diluted to the final volume of 250.0 mL.  Then 15.0…

A: Given that : The initial volume of H3PO4 = 10.0 mL The final volume of H3PO4 = 250.0 mL Molarity of…

Q: When 38.0 mL of 0.1250 M H2SO4 is added to 100. mL of a solution of PbBr2, a precipitate of PbSO4…

A: Mass of PbSO4 = 0.0471 g Molar mass of PbSO4 =303.28 g/mol Volume of PbBr2 = 100 mL

Q: A sample of an iron ore is dissolved in acid, and the iron is converted to Fe2+. The sample is then…

A: (a) Given, volume of MnO4- = 47.20 mL Molarity = 0.00240 mol/L So, Number of moles of…

Q: A 1.04 g sample of KBr is dissolved in water to give 155 mL of solution. This solution is then added…

A: 1) Mass of KBr = 1.04 gCalculation of no. mol of KBr:n = given massmolar mass    = 1.04g119.002…

Q: A volumetric pipette was used to transfer 10.00 mL of HCI solution into a 125 mL Erlenmeyer flask. A…

A: Given: Concentration of NaOH = 0.9980 M Volume of NaOH solution dispensed = 15.50 mL And volume of…

Q: Federal regulations set an upper limit of 50 parts per million(ppm) of NH3 in the air in a work…

A: (a) The volume of HCl solution is 1.0 × 102 mL which is equal to 0.100 L and the volume of NaOH…

Q: The following balanced equations represent reactions that occur in aqueous base. Break them down…

A: Oxidation is defined as the increase in the oxidation number of the atom where as reduction is…

Q: Ascorbic acid (Vitamin C, H2C6H6O6) is a diprotic acid.  In a laboratory exercise, a vitamin C…

A: The balanced chemical equation of the ascorbic acid is - 1) calculate the moles of the base NaOH -…

Q: Calculate the initial thiocyanate ion concentration, [SCN ]o, in the reaction mixture obtained by…

A: To calculate initial concentration of thiocyanate ion , we would need moles of thiocyanate ion and…

Q: The exact neutralization of 10.00 mL of 0.1012 M H₂SO, (aq) requires 23.31 mL of NaOH What must be…

A:

Q: The zinc content of a 1.55 g ore sample was determined by dissolving the ore in HCl, which reacts…

A: According to the question we have, The mass of the sample ore is given by = 1.55 gm The volume of…

Q: By titration, it is found that 50.1 mL of 0.192 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given, Molarity of NaOH = 0.192 M Volume of NaOH = 50.1 ml Volume of HCl = 25.0 ml  Molarity of HCl…

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.