By titration, it is found that 50.1 mL of 0.192 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.   [HCl]=

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By titration, it is found that 50.1 mL of 0.192 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.
 
[HCl]=
 
By titration, it is found that 50.1 mL of 0.192 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.

\[[\text{HCl}] = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \text{M}\]

In this task, we have a titration setup where a solution of sodium hydroxide (NaOH) is used to determine the concentration of hydrochloric acid (HCl). The given data shows that:

- Volume of NaOH = 50.1 mL
- Concentration of NaOH = 0.192 M
- Volume of HCl = 25.0 mL

The problem requires calculating the concentration of the HCl solution. A box is provided for the answer, indicating the response should be in molarity (M).
Transcribed Image Text:By titration, it is found that 50.1 mL of 0.192 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution. \[[\text{HCl}] = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \text{M}\] In this task, we have a titration setup where a solution of sodium hydroxide (NaOH) is used to determine the concentration of hydrochloric acid (HCl). The given data shows that: - Volume of NaOH = 50.1 mL - Concentration of NaOH = 0.192 M - Volume of HCl = 25.0 mL The problem requires calculating the concentration of the HCl solution. A box is provided for the answer, indicating the response should be in molarity (M).
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