A 0.124 M NaOH(aq) solution was used to titrate 20.00 mL of an acetic acid (CH3COOH) solution that has an unknown concentration. The equivalence point is reached after adding 15.34 mL of NaOH(aq). a) Write out the complete balanced equation for the reaction that occurs in this titration. b) How man moles of NaOH were added to the acetic acid solution? c) How many moles of acetic acid were in the original 20.00 mL solution? d) What was the concentration of acetic acid in the orignial 20.00 mL solution?

Q: A sample of vinegar is to be analyzed for its acetic acid content. A volume of 50.0 mL is measured…

A: The volume of 1000.0 mL is equal to 1.0 L. The number of moles of NaOH or OH- in the 31.66 mL of…

Q: Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of…

A: We calculate normality of acid and base then use this formula N1V1 = N2V2

Q: To a 25.00 mL volumetric flask, a lab technician adds a 0.450 g sample of a weak monoprotic acid,…

A: Answer:- This question is answered by using the simple chemical reaction between acid and base. Then…

Q: By titration, it is found that 13.5 mL of 0.112 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Since the reaction taking place is given by  NaOH + HCl ----> NaCl + H2O Hence we can say that 1…

Q: 1. Which volume of 2.0 M NAOH (aq) is needed to completely neutralize 24 mL of 1.0 M HCI (aq)?

A: Applying molarity equation M1V1 = M2V2

Q: To a 25.00 mL volumetric flask, a lab technician adds a 0.200 g sample of a weak monoprotic acid,…

A: The reaction for the process is given below : HA  +  KOH  →  KA  +  H2O Given data : Concentration…

Q: To a 25.00 mL volumetric flask, a lab technician adds a 0.375 g sample of a weak monoprotic acid,…

A: To a weak acid when strong base is added a buffer solution is formed. pH of the buffer solution can…

Q: A chemistry student weighs out 0.113 g of ascorbic acid (H2C6H,06), a diprotic acid, into a 250. mL…

A: The mass of ascorbic acid is given as 0.113 g and the volume is 250 mL To calculate the volume of…

Q: To a 25.00 mL volumetric flask, a lab technician adds a 0.275 g sample of a weak monoprotic acid,…

A: Given:  Mass of acid(HA) = 0.275 gm  Molarity of base (KOH) = 0.0803 M  Volume of base at end point…

Q: Titration of a 25.00 mL sample of acid rain required 12.4 mL of 0.009879 M NaOH to reach the end…

A: Volume of sulphuric acid,V1 = 25.00mL Volume of NaOH,V2 = 12.4mL Concentration of NaOH,M2 =…

Q: Malonic acid, H2C3H2O4 (aq), is a diprotic acid, so 2 moles of hydroxide ions are required per mole…

A: A neutralization reaction can be described as a chemical reaction in which acid and base react…

Q: A 13.8 mL solution of 0.176 M phosphoric acid (ag) is to be titrated with 0.384 M sodium hydroxide…

A: The given data contains, Molarity of phosphoric acid = 0.176 M. Volume of phosphoric acid = 13.8 ml.…

Q: Oxalic acid dihydrate (H2C2O4 2H2O) can be used to standardize NaOH solution through acid-base…

A: The acid-base titration involves the reaction of an acid with a base to calculate the concentration…

Q: An analytical chemist weighs out 0.193 g of an unknown diprotic acid into a 250 mL volumetric flask…

A:

Q: A 25.00 mL sample of acetic acid (CH3COOH) is titrated to the equivalence using 31.08 mL of 0.1978 M…

A:

Q: with distilled water. The technician then titrates this weak acid solution with 0.0841 M KOH. She…

A:

Q: An analytical chemist weighs out 0.181 g of an unknown diprotic acid into a 250 mL volumetric flask…

A: Let the diprotic acid be H2A. The reaction between the diprotic acid and NaOH is shown as: H2A +…

Q: By titration, it is found that 55.5 mL of 0.116 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: HCl(aq)  +   NaOH (aq)  ------>   NaCl (aq)   +   H2O (l) Number of moles of HCl = Number of…

Q: 6. A buffer is prepared by adding 20.0 g of sodium acetate (CH3COONa) to 500 mL of a 0.150 M acetic…

A:

Q: Calculate the molarity of an acetic acid solution if 34.57 mL of this solution is needed to…

A:

Q: An approximately 0.1 M NaOH solution is made by adding 4.0 g of solid NaOH to 1000 mL. of water. The…

A: Titration is a common laboratory method of quantitative analysis to determine the concentration of…

Q: A 1.054-g sample of KHP (potassium hydrogen phthalate, KHC3H404; molar mass = 204.22 g/mol) is…

A: Molarity of a solution is the number of moles of solute upon the volume of the solution in liters.…

Q: 2. A 25.0-mL sample of HNO3 (aq) is neutralized by 32.1 mL of 0.150 M KOH (aq). What is the molarity…

A: Solution :-Nitric acid on neutralisation reaction with pottasiumhydroxide gives pottasium nitrate…

Q: To a 25.00 mL volumetric flask, a lab technician adds a 0.125 g sample of a weak monoprotic acid,…

A: Given, Mass of weak monoprotic acid HA is ---- 0.125g Volume of solution made with it is…

Q: A 1.4350-gram of KHP (actual formula = KHC8H4O4; molar mass = 204.22 g/mol) was dissolved in 50.00…

A: We have given that KHC8H4O4(aq)  +  NaOH(aq) →   NaKC8H4O4(aq)  +  H2O(l) Mass of KHP = 1.4350g…

Q: A buffer is prepared by mixing hypochlorous acid (HCIO) and sodium hypochlorite (NaCIO). If a strong…

A:

Q: To a 25.00 mL volumetric flask, a lab technician adds a 0.425 g sample of a weak monoprotic acid,…

A: Henderson Hasselbach equation is used to determine the pKa of unknown acid in the given scenario. pH…

Q: A student titrated 30.mL of 0.15 M HF(aq) with 0.30 M NaOH(aq). The results are plotted on the…

A: The titration of HF with NaOH has been considered. The given questions have been solved based on the…

Q: A chemistry student weighs out 0.379g of citric acid H3C6H5O7, a triprotic acid, into a 250.mL…

A: Given : mass of H3C6H5O7 = 0.379 g  And concentration of NaOH = 0.2000 M  Since H3C6H5O7 is a…

Q: Hx (aq) + NaOH --> H2O (l) + Nax(aq) Calculate number of moles of NaOH that was needed to…

A: The titration reaction taking place is given as, => HX (aq) + NaOH (aq) ------> NaX (aq) + H2O…

Q: The titration of 0.314 g of potassium hydrogen phthalate (KHP) requires 13.16 mL of a NaOH solution.…

A:

Q: Oxalic acid dihydrate (H2C2O4 2H2O) can be used to standardize NaOH solution through acid-base…

A: The ratio of moles of solute to the volume of solution in liters in known as molarity.

Q: A certain brand of vinegar is analyzed for its acetic acid content by titration with 0.2 moles/liter…

A:

Q: By titration, it is found that 50.1 mL of 0.192 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given, Molarity of NaOH = 0.192 M Volume of NaOH = 50.1 ml Volume of HCl = 25.0 ml  Molarity of HCl…

Precipitation Titration

Precipitation analysis is used to analyze drugs, and to measure the salt content in food and beverages. It is an important concept from the examination point of view many practical questions are asked on the topic. This topic is significant in the professional exams for both undergraduate and graduate courses, especially for