A 0.124 M NaOH(aq) solution was used to titrate 20.00 mL of an acetic acid (CH3COOH) solution that has an unknown concentration. The equivalence point is reached after adding 15.34 mL of NaOH(aq). a) Write out the complete balanced equation for the reaction that occurs in this titration. b) How man moles of NaOH were added to the acetic acid solution? c) How many moles of acetic acid were in the original 20.00 mL solution? d) What was the concentration of acetic acid in the orignial 20.00 mL solution?

Q: A sample of vinegar is to be analyzed for its acetic acid content. A volume of 50.0 mL is measured…

A: The volume of 1000.0 mL is equal to 1.0 L. The number of moles of NaOH or OH- in the 31.66 mL of…

Q: Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of…

A: We calculate normality of acid and base then use this formula N1V1 = N2V2

Q: Acetic acid reacts with sodium hydroxide in the following fashion.  HC2H3O2(aq) + NaOH(aq)     →…

A:

Q: 7.7 g of citric acid (MM = 192.1 g/mol) can be titrated with NaOH according to the following…

A: By stoichiometry of reaction : At equivalent point : Moles of H3C6H5O7 = Moles of NaOH  given mass…

Q: If 48.1 g of C₂H₅OH (MM = 46.07 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Molar concentration or molarity (M) of a solution is defined as the number of moles of solute…

Q: A titration flask contains 0.00405 moles of an acetic acid sample   a. Determine the moles of the…

A: The given number of moles of acetic acid is 0.00405 mol. The molarity of NaOH is 0.200 M. The…

Q: A 4.500-g sample containing sodium bicarbonate (NaHCO3, 84.01 g/mol) and other substances is…

A: We will use the balanced neutralization reaction to find out the moles of NaHCO3, that are getting…

Q: A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs…

A:

Q: n analytical chemist weighs out 0.105 g of an unknown monoprotic acid into a 250 mL volumetric flask…

A: At equivalence point mole of standard solution is equal to the mole of unknown solution.

Q: 25.0 mL of 0.212 M NaOH is neutralized by 17.7  mL of an HCl solution according to the equation…

A:

Q: 2. Dilute sulphuric acid is a strong acid. (a) What is meant by a "strong" acid? (b) A student…

A: Given: Volume of dilute sulfuric acid = 25.0 cm3 = 25.0 mL   Trial-1 Trial-2 Trial-3 Trial-4…

Q: At the end of a titration, 40.00 mL of base was added. The molarity of the NaOH was 0.508 M. How…

A: Number of mols  of base is  = Volume in L × Molarity(mol/L)

Q: A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs…

A: First, we need to calculate the number of moles of oxalic acid (H2C2O4) used. The molar mass of…

Q: Before performing a titration of vinegar itself, you first had to standardize the solution used to…

A: As most base solutions are secondary standardized, so we need to standardise base solutions with a…

Q: A 25.00 mL sample of phosphoric acid (H3PO4) is titrated to the equivalence using 19.71 mL of 0.2056…

A: Answer: In acid-base reaction, neutralization takes place where hydrogen ions and hydroxide ions…

Q: 4. Complete and balance the following equations; then write balanced net ionic equations a.…

A: According to the law of conservation of mass, the quantity of each element does not change in a…

Q: By titration, it is found that 13.5 mL of 0.112 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Since the reaction taking place is given by  NaOH + HCl ----> NaCl + H2O Hence we can say that 1…

Q: An impure sample of potassium hydrogen phthalate (KHP) was titrated to determine the percent…

A: We will use stoichiometry of the reaction to get the answer.

Q: A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs…

A: Acid–base titration : It is a method of determining the concentration of an acid or base by…

Q: An analytical chemist weighs out 0.123 g of an unknown monoprotic acid into a 250 mL volumetric…

A:

Q: A solution of an unknown monoprotic acid was prepared by dissolving 72.9 mg of the acid into 50. mL…

A: Molarity is given by the number of moles per liter of the solution.

Q: A chemistry student weighs out 0.173 g of ascorbic acid (H₂CH₂O), a diprotic acid, into a 250. mL…

A:

Q: An aqueous solution of Ca(OH)2with a concentration of 0.200 M was used to titrate 25.00 mL of…

A: Given ->  Molarity of Ca(OH)2 = 0.200 M = M1 Volume of Ca(OH)2 = 17.73 ml = 0.01773 L = V1 (1L =…

Q: Malonic acid, H2C3H2O4 (aq), is a diprotic acid, so 2 moles of hydroxide ions are required per mole…

A: A neutralization reaction can be described as a chemical reaction in which acid and base react…

Q: Consider the following acid base titration between H2C3H5O3 (aq) with KOH (aq).    A)Write a…

A:

Q: An aqueous solution of Ca(OH)2with a concentration of 0.188 M was used to titrate 25.00 mL of…

A:

Q: A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs…

A: Given: Mass of oxalic acid = 10 mg Volume of oxalic acid = 250 mL Volume of NaOH solution = 12.2 mL…

Q: Titration of a 20.00 mL sample of acid rain required 4.13 mL of 0.08424 M KOH to reach the end…

A: The given reaction is, H2SO4- + 2KOH -----> K2SO4 + 2H2O This means that 2 moles of KOH is…

Q: unknown acid, which can be either oxalic acid, H2C2O4, or citric acid, H3C6H5O7. To determine which…

A: I m not getting why you have written moles of NaOH and oxalic acid after that .We have to find it…

Q: the concentration of the Sodium hydroxide solution.

A:

Q: A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs…

A:

Q: Through this reaction HCl(aq) + NaHCO3(aq)— NaCl(aq) +H2O(l) +CO2(g). The CO2 gas produced is what…

A:

Q: An analytical chemist weighs out 0.127 g of an unknown monoprotic acid into a 250 mL volumetric…

A: Given:-analytical chemist weighs = 0.127 gMolarity = 0.1800MV = 9.3 mLCalculate molar mass of the…

Q: A chemistry student weighs out 0.361 g of ascorbic acid (H₂C H₂O), a diprotic acid, into a 250. ml.…

A:

Q: A 13.8 mL solution of 0.176 M phosphoric acid (ag) is to be titrated with 0.384 M sodium hydroxide…

A: The given data contains, Molarity of phosphoric acid = 0.176 M. Volume of phosphoric acid = 13.8 ml.…

Q: A sample weighing 1.731g contains a mixture of the triprotic citric acid, H3C6H5O7 and sodium…

A: Given, Mass of the mixture = 1.731 g Molarity of sodium hydroxide, NaOH = 0.3550 M = 0.3550 mol/L…

Q: An analytical chemist weighs out 0.193 g of an unknown diprotic acid into a 250 mL volumetric flask…

A:

Precipitation Titration

Precipitation analysis is used to analyze drugs, and to measure the salt content in food and beverages. It is an important concept from the examination point of view many practical questions are asked on the topic. This topic is significant in the professional exams for both undergraduate and graduate courses, especially for