(II) A 172-cm-tall person lies on a light (massless) boardwhich is supported by two scales, one under the top of herhead and one beneath the bottom of her feet (Fig. 9–64).The two scales read, respectively, 35.1 and 31.6 kg. Whatdistance is the center of gravity of this person from thebottom of her feet?35.131.6KILOGRAMSKILOGRAMSFIGURE 9-64 Problem 24.

The expression for the Center of gravity CG is given by CG=W1d1+W2d2W1+W2 Where W1 and W2 are the…

Answered: (II) A 172-cm-tall person lies on a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The center of mass of a rigid body always lies inside the body. Is this statement true or false? Why?
To strengthen his arm and chest muscles, a 79-kg athlete 2.0 m tall is doing a series of push-ups as shown in the figure below (Figure 1). His center of mass is 1.20 m from the bottom of his feet, and the centers of his palms are 30.0 cm from the top of his head. Figure 1 of 1 > 20m -300 Review Find the force that the floor exerts on each of his feet, assuming that both feet exert the same force. Express your answerin newtons. 16] ΑΣΦ ? F-125.24 Submit Previous Answers Request Answer * Incorrect; Try Again; 4 attempts remaining Part B Find the force that the floor exerts on each of his hands, assuming both palms exert the same force. Express your answer in newtons. LIVE ΑΣΦΑ F-114 N Submit Previous Answers Request Answer * Incorrect; Try Again; 5 attempts remaining P Pearson N
(5) We typically place our arms out for when we are crossing a narrow beam/rope. Is it because: (a) The larger leg muscles are unable to be used so we use the arms for leverage to bring our line of gravity back inside base of support; (b) To make our body area wider so the base of support is wider and line of gravity falls within it; (c) To make our body area wider so center of gravity naturally becomes lower and the body is more stable; (d) To utilize force summation to use larger muscles to bring us back into balance
A 2.0-m-high box with a 1.0-m-square base is moved across a rough floor as in Fig. 9–89. The uniform box weighs 250N and has a coefficient of static friction with the floor of 0.60. What minimum force must be 1.0 m exerted on the box to make it slide? What is the maximum height h above the floor that this force can be applied without tip- ping the box over? Note that as the box tips, the normal force CG 2.0 m FN and the friction force will act at the lowest corner. Fir FIGURE 9-89 Problem 74.
Why is it not possible to sit upright in a chair and rise toyour feet without first leaning forward?
What happens to the center of gravity of a person under the following situations? a) His upper right extremity is amputated. b) He carries all his books using the right arm only.
3) To strengthen his arm and chest muscles, a 6-slug athlete who is 6'6" tall is doing push-ups as shown in the figure below. His centre of mass is 3'9" from the bottom of his feet, and the centres of his palms are one foot from the top of his head. Find the force that the floor exerts on each of his feet and on each hand, assuming that both feet exert the same force and both palms do likewise. Begin with a free-body diagram of the athlete. 6'6" K–1'-
A hand exerts a force of 25 lbs on a scale at 16 inches from the joint center at the elbow. If the triceps attach to the ulna at a 90° angle and at a distance of 2.5 cm from the elbow joint center, and if the weight of the forearm and hand is 12 lbs with the hand/forearm CG located 15 cm from the elbow joint center, how much force is being exerted by the triceps? 880 1488 N 8800 O 15.640 N Onone of the answers are correct

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