If z is a standard normal random variable, then P (1.83 < z < 2.38) is:
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If z is a standard normal random variable, then P (1.83 < z < 2.38) is:
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- Find a value of the standard normal random variable z , call it z0, such that the following probabilities are satisfied. a. P(z≤z0)=0.3089 d. P(−z0≤z<z0)=0.1782 b. P(z≤z0)=0.9527 e. P(z0≤z≤0)=0.3009 c. P(−z0≤z<z0)=0.8386 f. P(−1<z<z0)=0.5921Let x be a normally distributed random variable with the following parameters: μ = 135.628 σ = 28.622 12 What is the probability that x will be below 100 ? a 0.1343 b 0.1243 c 0.1151 d 0.1066For the standard normal random variable z, compute the following probabilities (if required, round your answers to four decimal places): P (z ≥ −0.23) = P (z < 1.20) = P (z ≤ −0.71) =
- Find the following probability for the standard normal random variable z. a. P(z=2) e. P(-2≤z≤2) b. P(z ≤2) f. P(-1≤z≤1) c. P(Z 2) h. P(-0.35Find the following probabilities for the standard normal random variable z. P(-2.28Let Z be a standard normal variable. Find the value of z if z satisfies P(Z > z) = 0.6331. a) 00.35 b) O-0.3 с) О-034 d) 00.34 e) 00.30 D O None of the above. Question 29 Suppose X is a normal random variable with u = 35 and o = 10. Find P(21.4 < X < 39.7). a) 005586 b) 00.5337 c) O0.5939 d) O0.2323 e) 0 0.2478 f) O None of the above.Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). a. P(-1.98 < z< 0.49) b. P(0.58Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). a. P(-1.98 < z< 0.49) b. P(0.56 < z < 1.29) c. P(-1.73 < z < -1.07) O O ORecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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