If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT = -0.45
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4: If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT = -0.45
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- Suppose 235 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20% of users develop nausea.The test statistic for this hypothesis test is .(Round to two decimal places as needed.)What is the formula for a two tailed test?In 2005, Health Canada claimed that 16.9% of Canadian adults are obese. A researcher wanted to check whether this percentage has changed in 2009. In 2009, he randomly selected 90 Canadian adults and found 12 of them are obese. Use a 7% significance level. The decision rule is either Reject Ho if Zcalc > 1.48 Reject Ho if Zcalc > 1.81 Reject H0 if Zcalc < -1.81 or Zcalc > 1.81 Reject H0 if Zcalc < -1.48 or Zcalc > 1.48
- USA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1008 Chevrolet owners and found that 481 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than 47%? Use ? = 0.01. (a) What is the level of significance?State the null and alternate hypotheses. H0: p = 0.47; H1: p > 0.47H0: p = 0.47; H1: p < 0.47 H0: p > 0.47; H1: p = 0.47H0: p = 0.47; H1: p ≠ 0.47 (b) What sampling distribution will you use? The standard normal, since np > 5 and nq > 5.The standard normal, since np < 5 and nq < 5. The Student's t, since np > 5 and nq > 5.The Student's t, since np < 5 and nq < 5. What is the value of the sample test statistic? (Round your answer to two decimal places.)(c) Find the P-value of the test statistic. (Round your answer to four…Suppose a hypothesis test was performed with a level of significance of 0.05. Then if the null hypothesis is actually true, then there is a 5% chance that the researcher will end up rejecting the null hypothesis in error. True FalseUSA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1008 Chevrolet owners and found that 487 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than 47%? Use ? = 0.01. (a) What is the level of significance?State the null and alternate hypotheses. H0: p > 0.47; H1: p = 0.47H0: p = 0.47; H1: p ≠ 0.47 H0: p = 0.47; H1: p < 0.47H0: p = 0.47; H1: p > 0.47 (b) What sampling distribution will you use? The standard normal, since np < 5 and nq < 5.The standard normal, since np > 5 and nq > 5. The Student's t, since np < 5 and nq < 5.The Student's t, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.)(c) Find the P-value of the test statistic. (Round your answer to four…
- According to a book published in 2011, 45% of the undergraduate students in the United States show almost no gain in learning in their first two years of college (Richard Arum et al., Academically Adrift, University of Chicago Press, Chicago, 2011). A recent sample of 1540 undergraduate students showed that this percentage is 37%. Can you reject the null hypothesis at a 2.5% significance level in favor of the alternative that the percentage of undergraduate students in the United States who show almost no gain in learning in their first two years of college is currently lower than 45%. Use both the p-value and the critical-value approaches. Round your answers for the observed value of z and the critical value of z to two decimal places, and the p-value to four decimal places. Zobserved = p-value = Critical value = i Hence we can conclude that the percentage of undergraduate students in the U.S. who show almost no gain in learning in their fırst two years of college is currently 45%.Prof. Johnson conducts a hypothesis test on whether the proportion of all UBC students who bike to school (denoted as p) equals 30%. Specifically, Prof.Johnson has H0:p=0.3 versus HA:p≠0.3. He obtains a P-value of 0.01. On the other hand, Prof. Smith would like to test if there is sufficient evidence to support that p is greater than 0.3 at the 10% significance level. Based on Prof. Johnson's result, will the null hypothesis of Prof. Smith's test be rejected? A. There is insufficient information to tell.B. Yes.C. No.A graduate student believes that people consider faces with more contrast between lip color and skin tone as more feminine. She identifies the null hypothesis as: Ho: The level of contrast between lip color and skin tone does not affect how feminine a face is considered. She chooses a significance level of 0.05. After she collects the data and computes the sample statistics, it is time for her to make a decision about the null hypothesis. What are the two possible decisions that the graduate student can make? Check all that apply. There is not enough evidence to reject the hypothesis that the contrast between lip color and skin tone affects how feminine a face is considered. There is enough evidence to reject the hypothesis that the contrast between lip color and skin tone does not affect how feminine a face is considered. There is enough evidence to reject the hypothesis that the contrast between lip color and skin tone affects how feminine a face is considered. ☐ There is not enough…
- A Two tailed test, where the null hypothesis is H0: p = 0.95 and the significance level is 10%. When the edge of the rejection region for the lower tail is 0.9399 then what is the value of "?" in P(P-hat > ? | p = 0.95) = 0.05?A barangay captain claims that at least 25% of the residents in his barangay have household pets. To test this claim a researcher randomly selected a sample of 50 residents and find that 13 of them do have pets. What can you conclude at 0.10 level of significance.One study claimed that 88 % of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 272 college students and finds that 231 of them identify themselves as procrastinators. Does this evidence support the professor's claim that fewer than 88 % of college students are procrastinators? Use a 0.02 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho p = 0.88 Ha P 0.88
