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If (x) is a string, the text is displayed. ; >> x= [1 2 3] x = 123 O disp(x) 1 2 3 O >> x x = 1 2 3, >> disp(x) 1 2 3 O 123 O

If (x) is a string, the text is displayed. ; >> x= [1 2 3] x = 123 O disp(x) 1 2 3 O >> x x = 1 2 3, >> disp(x) 1 2 3 O 123 O

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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### Understanding String Display in Programming #### Problem Statement: Given the information, "If `( x )` is a string, the text is displayed." ```plaintext ; >> x=[1 2 3] ``` Determine the correct way to display the text if `( x )` is a string. Select one of the following options: 1. ```x = 1 2 3``` ![Radio Button](http://example.com/radiobutton) 2. ```disp(x) 1 2 3``` ![Radio Button](http://example.com/radiobutton) 3. ```>> x x = 1 2 3, >> disp(x) 1 2 3``` ![Radio Button](http://example.com/radiobutton) 4. ```1 2 3``` ![Radio Button](http://example.com/radiobutton) --- In this example, we aim to evaluate the expression `( x )` if it is a string and deduce the right method to display the text. The syntax `; >> x=[1 2 3]` suggests assigning a vector to variable `x`. ##### Options Explained: 1. **Option 1: "x = 1 2 3"** - This suggests assigning values to `x` and displaying the assignment structure, but does not directly display the string itself. 2. **Option 2: "disp(x) 1 2 3"** - The `disp(x)` function displays the value of `x` if it is a string. However, the inclusion of `1 2 3` after the `disp` function syntax is incorrect. 3. **Option 3: ">> x x = 1 2 3, >> disp(x) 1 2 3"** - This shows the assignment and display of `x` but merges multiple statements incorrectly. 4. **Option 4: "1 2 3"** - This indicates simply displaying the string values assigned to `x`, assuming it represents the string `'1 2 3'`. The goal is to determine the correct method for displaying the text `1 2 3` if `( x )` originally represents this string. --- Q: Identify the correct option for the output of string `( x )`: > 1
Transcribed Image Text:### Understanding String Display in Programming #### Problem Statement: Given the information, "If `( x )` is a string, the text is displayed." ```plaintext ; >> x=[1 2 3] ``` Determine the correct way to display the text if `( x )` is a string. Select one of the following options: 1. ```x = 1 2 3``` ![Radio Button](http://example.com/radiobutton) 2. ```disp(x) 1 2 3``` ![Radio Button](http://example.com/radiobutton) 3. ```>> x x = 1 2 3, >> disp(x) 1 2 3``` ![Radio Button](http://example.com/radiobutton) 4. ```1 2 3``` ![Radio Button](http://example.com/radiobutton) --- In this example, we aim to evaluate the expression `( x )` if it is a string and deduce the right method to display the text. The syntax `; >> x=[1 2 3]` suggests assigning a vector to variable `x`. ##### Options Explained: 1. **Option 1: "x = 1 2 3"** - This suggests assigning values to `x` and displaying the assignment structure, but does not directly display the string itself. 2. **Option 2: "disp(x) 1 2 3"** - The `disp(x)` function displays the value of `x` if it is a string. However, the inclusion of `1 2 3` after the `disp` function syntax is incorrect. 3. **Option 3: ">> x x = 1 2 3, >> disp(x) 1 2 3"** - This shows the assignment and display of `x` but merges multiple statements incorrectly. 4. **Option 4: "1 2 3"** - This indicates simply displaying the string values assigned to `x`, assuming it represents the string `'1 2 3'`. The goal is to determine the correct method for displaying the text `1 2 3` if `( x )` originally represents this string. --- Q: Identify the correct option for the output of string `( x )`: > 1
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