If we use t0.05, df=10 to denote the value that cuts a lower tail of 0.05 from a tdistribution with 10 degrees of freedom.If we use to.95, df=10 to denote the value that cuts a lower tail of 0.95 from a t distributionwith 10 degrees of freedom.What can you say about these two values?>Oto.05,df 10 to.95, df=10○ to.05,df=10 + to.95,df=10 = 1Ot0.95,df=10=-t0.05,df=10

The question is asking us to compare two values from a t-distribution with 10 degrees of freedom.…

Answered: If we use t0.05, df=10 to denote the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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i Mon 6:43 PM File Edit View History Bookmarks Window Help Safari + www-awn.connectmath.com Find the z value to the left of the mean so that 51.23% of the area under the distribution curve lies to the right of it. Use a graphing calculator and round the answer to four decimal places. NOV 25 MacBook A F12 F8 FI0 F11 F7 F9 F6 esc F5 F4 F3 F1 & $ delete 8 7 11 6 5 4 2 { Y T R E Q tab enter K H F D S retur ops lock B C X alt alt option command option control command (c. V NM
The pie chart shows the distribution of the opinions of parents on whether a college education is worth the expense. An economist claims that the distribution of the opinions of teenagers is different from the distribution for parents. To test this claim, you randomly select 197 teenagers and ask each whether a college education is worth the expense. Strongly agree The table to the right shows the results. At a = 0.05, test the economist's claim. Click the icon for the pie chart of the distribution. Response Somewhat agree Neither agree nor disagree Somewhat disagree Strongly disagree Survey results State Ho and H₂ and identify the claim. Ho: The distribution of the opinions of whether a college education is worth the expense is the same for teenagers and parents. Ha: The distribution of the opinions of whether a college education is worth the expense is different for teenagers and parents. Which hypothesis is the claim? Ho На Calculate the test statistic. 2 x = (Round to three decimal…
One graph in the figure represents a normal distribution with mean u= 15 and standard deviation o = 2. The other graph represents a normal distribution with mean u=11 and standard deviation o = 2. Determine which graph is which and explain how you know. A B 11 15 ... Choose the correct answer below. O A. Graph A has a mean of u = 15 and graph B has a mean of u = 11 because a larger mean shifts the graph to the right. O B. Graph A has a mean of u = 11 and graph B has a mean of u= 15 because a larger mean shifts the graph to the left. O C. Graph A has a mean of u = 11 and graph B has a mean of u = 15 because a larger mean shifts the graph to the right. O D. Graph A has a mean of u = 15 and graph B has a mean of u = 11 because a larger mean shifts the graph to the left.
The histogram has a longer tail/appears roughly the same/has a longer right tail so the distribution of the data is not skewed/skewed to the left/ skewed to the right
S, D, m5 w5 16. The mean of marks in Statistics of 100 students in a class was 72. The mean of marks of boys was 75, while their number was 70. Find out the mean marks of girls in the class.
Suppose X - N (8, 2). Between what a values does 68.22% of the data lie? The range of x values is centered at the mean of the distribution (i.e., 8). Enter your answers in increasing order, to the nearest integer. 68.22% of the data lie between Number and Number
HI T F. %24 E Z. Find the margin of error for the given values of c, s, and n. c = 0.98, s= 2.9, n = 21 Click the icon to view the t-distribution table. The margin of error is (Round to one decimal place as needed.) Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check Answer e Type here to search 查。 F1 F2 F3 F4 F5 %23 & 3. 4. 9.
Must the variable under consideration be normally distributed for you to use the ?-interval procedure or ?-interval procedure? Explain your answer.
You were creating a run chart using non- metric data and found that n_1 for run-ups was 14, and n_2 for run-downs was 14. What was your V(R)? 1.96 6.74 11.03 14.00
After three exams Denny has a mean score of 74 with only one exam remaining in the class what is the minimum score she will need on that exam to have an overall of an 80
Choose the best statement to summarize the association shown between hat size and IQ in the scatterplot below. Hat Size O The scatterplot does not show a trend that would indicate an association between hat size and IQ scores. O As hat size increases, IQ scores tend to decrease. O As hat size increases, IQ scores tend to increase. Hat size causes IQ to increase.
The average American gets a haircut every 34 days. Is the average smaller for college students? The data below shows the results of a survey of 15 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 23, 32, 38, 31, 39, 35, 25, 30, 36, 40, 27, 23, 32, 25 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv Hi: ?vSelect an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is 2v a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that.. O The data suggest the population mean is not significantly lower than 34 at a = 0.10, so there M 24 3. 4. 5 6. 7 EU

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