If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be AB? Enter your answer as a decimal to three places (for example: 0.120). Part B: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be Ab? Part C: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be aB? Part D: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a signal plant will be ab?

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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Part A: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be AB? Enter your answer as a decimal to three places (for example: 0.120). Part B: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be Ab? Part C: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a single plant will be aB? Part D: If the two genes are 30 mu apart and the plant is (AB/ab), what proportion of gametes from a signal plant will be ab?
**Linked Genes and Phenotypic Ratios: An Example**

In this example, we explore the genetic cross between two heterozygous plants, focusing on two linked gene pairs: \(AB/ab\). These loci are situated 30 map units (mu) apart on the chromosome. As a reminder, 1 mu corresponds to a 1% recombination frequency between two genes.

When we examine this genetic cross, we assume that crossing over can occur during the formation of both male and female gametes. The alleles \(A\) and \(B\) are dominant, which plays a crucial role in determining the traits observed in the offspring.

Given these conditions, we are tasked with determining the phenotypic ratio of the offspring. Understanding the degree of recombination due to the 30 mu distance is key to predicting the observed traits accurately.
Transcribed Image Text:**Linked Genes and Phenotypic Ratios: An Example** In this example, we explore the genetic cross between two heterozygous plants, focusing on two linked gene pairs: \(AB/ab\). These loci are situated 30 map units (mu) apart on the chromosome. As a reminder, 1 mu corresponds to a 1% recombination frequency between two genes. When we examine this genetic cross, we assume that crossing over can occur during the formation of both male and female gametes. The alleles \(A\) and \(B\) are dominant, which plays a crucial role in determining the traits observed in the offspring. Given these conditions, we are tasked with determining the phenotypic ratio of the offspring. Understanding the degree of recombination due to the 30 mu distance is key to predicting the observed traits accurately.
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