If the estimated power of a significance test is 0.6, it means that
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If the estimated power of a significance test is 0.6, it means that
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- Suppose a poll is taken that shows that 281 out of 500 randomly selected, independent people believe the rich should pay more taxes than they do. Test the hypothesis that a majority (more than 50%) believe the rich should pay more taxes than they do. Use a significance level of 0.05.Suppose that Dietitians recently recommended a 400 cal per meal and take her children of the age of the data set. To see if both groups adhere to the guideline follow the steps to develop and test a statistical hypothesis. Test to see if us groups means are different from 400 calories. You have two data sets so you'll be completing the process twice. Use 0.05 as a level of significance and make sure to report any important statistic with your results (e.g., mean of each group, standard deviation of each group, test stastistic (are you using t or z?), rejection region and p value). Data: Children Participated Children Did Not Participate 435.16 414.61 338.99 503.46 488.73 425.22 590.28 288.77 582.59 184 635.21 299.73 249.86 350.65 441.66 394.94 572.43 261.55 357.78 295.28 396.79 139.69 298.38 462.78 282.99 179.59 368.51 301.75 388.59 436.58 256.32 371.39 408.82 469.02 424.94 378.09 477.96 287.31 428.74 448.55 432.52 332.64 428.27…Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x=103.36, y=103.45, r=0.928, P-value= 0.000, and y=−7.2+1.07x,where x represents the IQ score of the older child.Find the best predicted value of y given that the older child has an IQ of 106? Use a significance level of 0.05
- Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 98.46, y = 99.4, r=0.883, P-value = 0.000, and y=-14.65 +1.16x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 101? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)Historically, the percentage of U.S. residents who support stricter gun control laws has been 55%. A recent Gallup Poll of 2500 people showed 1723 in favor of stricter gun control laws . Assume the poll was given to a random sample of people. QUESTION Test the claim that the proportion of those favoring stricter gun control has changed from 0.55. Perform a hypothesis test, using a significance level of 0.01. What kind of test will you need to perform? A right, one-tailed z-test A left, one-tailed z-test A two-tailed z- testSuppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x=101.22, y=102.45, r=0.916, P-value=0.000, and y=−8.44+1.1x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 99? Use a significance level of 0.05.
- A sociologist claims that the students’ college GPA’s in unrelated to their families’ incomes. For a random sample of 20 students the coefficient of correlation was computed as 0.40. Using the 0.01 significance level, do the formal hypothesis test.Remember to show your steps (including all relevant information) show the steps on how to solve itSuppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 101.13, y = 103.5, r=0.867, P-value = 0.000, and y = 6.25 +0.96x, where x represents the IQ score of the younger child. Find the best predicted value of y given that the younger child has an IQ of 101? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of ŷ is. (Round to two decimal places as needed.)Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…
- During the 1990s, the fatality rate for lung cancer was 80 per 100,000 people. After the turn of the century and the establishment of newer treatments and adjustment in public health advertising, a random sample of 10,000 people exhibits only six deaths due to lung cancer. Test at the 0.05 significance level whether that data are proof of a reduced fatality rate for lung cancer. b. Make the decision rule. (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.) c. Evaluate the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)The accompanying table contains the data for the amounts (in oz) in cans of a certain soda. The cans are labeled to indicate that the contents are 16 oz of soda. Use the sign test and a 0.01 significance level to test the claim that cans of this soda are filled so that the median amount is 16 oz. If the median is not 16 oz, are consumers being cheated? Click the icon to view the data. What are the null and alternative hypotheses? O A. Ho: Median volume ≤ 16 oz H₁: Median volume = 16 oz C. Ho: Median volume = 16 oz H₁: Median volume # 16 oz Find the test statistic. Test statistic (Round to three decimal places as needed.) = More Info 15.6 16.0 16.1 16.1 407 15.7 (…) 16.1 15.9 19:3 15.8 16.5 15.8 15.7 15.9 OB. Ho: Median volume ≤ 16 oz H₁: Median volume > 16 oz O D. Ho: Median volume = 16 oz H₁: Median volume < 16 oz Volume (in ounces) 15.7 15.5 15.7 15.7 15.8 420 15.9 103 16.3 15.7 15.7 16.1 16.3 15.8 15.7 15.6 15.5 15.6 15.5 20 16.0 400 15.8 19:0 15.6 15.6 15.5 16.4 15.9 D - XSuppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x= 100.1, y = 98.3, r=0.961, P-value = 0.000, and y = - 18.02 + 1.16x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 100? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)
