If n = 526 and (p - hat )= 0.30, find the margin of error at a 98% confidence level
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If n = 526 and (p - hat )= 0.30, find the margin of error at a 98% confidence level
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- The 82.9% confidence interval estimate for μμ was (25.81, 31.35). Find the point estimate and the margin of error (ME) from this interval estimate. Point estimate = ME=To calculate 95% confidence interval we must multiply the standard error by 3, then add and subtract the result to the best estimate. add and subtract the standard error to the best estimate. multiply the standard error in y-intercept by 2, then add and subtract the result to the slope of the graph. multiply the standard error by 2, then add and subtract the result to the best estimate.suppose a random sample of 25 observation from a normal population with standard deviation 6. Also the sample mean is 20. Find 90% confidence interval for the population mean.
- FIND Za/2 FOR THE 86 % CONFIDENCE INTERVALThe 92% confidence interval for the true proportion of Lexus cars in Muscat city is 0.1<P<0.2. What was point estimate of the proportion and the sample size used to get this interval?The researcher recorded the amount of time each bird spent in the plain chamber during a 60-minute session. Suppose the study produced a mean of M = 51.38 minutes on the plain chamber with SS = 3898 for a sample of n = 14 birds. Construct the 90% confidence interval to estimate the mean amount of time spent on the plain side for the population of birds. Type only the upper interval by using Nearest hundredths place.
- A city planner wants to estimate the average monthly residential water usage in the city. He selected a random sample of 42 households from the city, which gave the mean water usage to be 3409.30 gallons over a one-month period. Based on earlier data, the population standard deviation of the monthly residential water usage in this city is 387.90 gallons. Make a 97% confidence interval for the average monthly residential water usage for all households in this city.A researcher collected sample data for 15 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 192.7, with a standard deviation of 6. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 99% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: Upper limit: X ŚA researcher collected sample data for 20 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 190.4, with a standard deviation of 9.7. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 99% confidence interval.Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place Lower limit= Upper limit=
